The given equi-convex lens is broken int...

The given equi-convex lens is broken into four parts and rearranged as shwon. If the initial focal length is f, then after rearrangement the equivalent focal length is

A

`f`

B

`f//2`

C

`f//4`

D

`4f`

Text Solution

Verified by Experts

The correct Answer is:

B

Focal length of any one part will be `2f.`
`:. 1/F=1/(2f)+1/(2f)+1/(2f)+1/(2f) or F=f/2`

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