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The angle of minimum deviation for a gla...

The angle of minimum deviation for a glass prism with `mu=sqrt3` equals the angle of the prism. What is the angle of the prism?

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To solve the problem, we need to find the angle of the prism (denoted as \( a \)) given that the angle of minimum deviation (\( \delta_m \)) is equal to the angle of the prism and the refractive index (\( \mu \)) is \( \sqrt{3} \). ### Step-by-Step Solution: 1. **Understanding the Relationship**: We know that for a prism, the refractive index \( \mu \) can be expressed in terms of the angle of minimum deviation (\( \delta_m \)) and the angle of the prism (\( a \)) using the formula: \[ \mu = \frac{\sin\left(\frac{\delta_m + a}{2}\right)}{\sin\left(\frac{a}{2}\right)} ...
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DC PANDEY ENGLISH-REFRACTION OF LIGHT-Level 1 Subjective
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