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In the figure ABC is the cross-section o...

In the figure ABC is the cross-section of a right angled prism and BCDE is the cross-section of a glass slab. The value of theta so that light incident normally on the face AB does not cross the face BC is `(Given sin^-1 3//5=37^@)`

A

`thetalt37^@`

B

`thetalt53^@`

C

`thetage37^@`

D

`thetage53^@`

Text Solution

Verified by Experts

The correct Answer is:
A
`sin theta_C=(mu_R)/mu_D=(6//5)/(3//2)=4/5`
`r_1=0^@ rArr r_2= lt B=90^@-theta`
Now, `r_2gt theta_c`
or `sinr_2gtsin theta_C`
`:. Sin(90^@-theta)gt4/5`
or `cos thetagt4/5…(i)`
`cos 37^@=4/5`
From Eq. (i), we see that
`thetalt37^@`
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