Home
Class 12
PHYSICS
Two waves of equal frequencies have thei...

Two waves of equal frequencies have their amplitude in the ratio of 5:3. They are superimposed on each other. Calculate the ratio of the maximum to minimum intensities of the resultant wave.

Text Solution

AI Generated Solution

To solve the problem of finding the ratio of maximum to minimum intensities of two superimposed waves with given amplitude ratios, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Amplitude Ratio**: Given that the amplitudes of the two waves are in the ratio of 5:3, we can denote the amplitudes as: \[ A_1 = 5k \quad \text{and} \quad A_2 = 3k ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Subjective Questions|5 Videos
  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Level 2 Single Correct|11 Videos
  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Objective question|2 Videos
  • GRAVITATION

    DC PANDEY ENGLISH|Exercise All Questions|135 Videos
  • MAGNETIC FIELD AND FORCES

    DC PANDEY ENGLISH|Exercise Medical entrance s gallery|59 Videos

Similar Questions

Explore conceptually related problems

Two waves of equal frequencies have their amplitudes in the ratio of 3:5. They are superimposed on each other. Calculate the ratio of maximum and minimum intensities of the resultant wave.

The ratio of the intensities of two interfering waves is 81:1. What is the ratio of the maximum to minimum intensity?

Knowledge Check

  • Two waves of the same pitch have amplitudes in the ratio 1 : 3. What will be the ratio of their : frequencies?

    A
    1:9
    B
    9:1
    C
    1:1
    D
    no change
  • Similar Questions

    Explore conceptually related problems

    When two waves of amplitudes A_1 and A_2 superpose each other what is the ratio of maximum intensity to the minimum intensity.

    Two coherent plane progressive waves are represented by [y_1 = sin (200 pi t - 100 pix)] and [y_2 = 2sin (200pit-100pi x + phi)] are superimposed on each other, Then the ratio of maximum and minimum intensity of the resultant wave will be

    Two waves having the intensities in the ratio of 9 : 1 produce interference. The ratio of maximum to minimum intensity is equal to

    When two coherent monochromatic light beams of intensities I and 4I are superimposed, the ratio between maximum and minimum intensities in the resultant beam is

    If the ratio of amplitude of two waves is 4:3 , then the ratio of maximum and minimum intensity is

    The ratio of intensities of two waves is 9 : 1 When they superimpose, the ratio of maximum to minimum intensity will become :-

    The ratio of intensities of two waves is 9 : 1 When they superimpose, the ratio of maximum to minimum intensity will become :-