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Electrons with energy 80 keV are inciden...

Electrons with energy `80 keV` are incident on the tungsten target of an X - rays tube , k- shell electrons of tungsten have `72.5 keV` energy X- rays emitted by the tube contain only

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To solve the problem, we need to analyze the situation where electrons with energy of 80 keV are incident on a tungsten target, and we need to determine the characteristics of the X-rays emitted from this interaction. ### Step-by-Step Solution: 1. **Identify the Energy of Incident Electrons**: The energy of the incident electrons is given as \( E = 80 \, \text{keV} \). 2. **Identify the Binding Energy of K-shell Electrons**: The binding energy of the K-shell electrons in tungsten is given as \( E_k = 72.5 \, \text{keV} \). 3. **Determine if K-shell Electrons Can Be Ejected**: Since the energy of the incident electrons (80 keV) is greater than the binding energy of the K-shell electrons (72.5 keV), the incident electrons can knock out K-shell electrons from the tungsten atoms. 4. **Calculate the Minimum Wavelength of the X-rays**: The energy of the emitted X-rays can be calculated using the formula relating energy and wavelength: \[ E = \frac{hc}{\lambda} \] Rearranging this gives: \[ \lambda = \frac{hc}{E} \] Here, \( h \) (Planck's constant) is approximately \( 4.135667696 \times 10^{-15} \, \text{eV s} \) and \( c \) (speed of light) is approximately \( 3 \times 10^8 \, \text{m/s} \). 5. **Convert Energy to Joules**: First, we convert the energy from keV to joules: \[ E = 80 \, \text{keV} = 80 \times 10^3 \, \text{eV} = 80 \times 10^3 \times 1.6 \times 10^{-19} \, \text{J} = 1.28 \times 10^{-14} \, \text{J} \] 6. **Calculate the Wavelength**: Now substituting the values of \( h \), \( c \), and \( E \) into the wavelength formula: \[ \lambda = \frac{(4.135667696 \times 10^{-15} \, \text{eV s})(3 \times 10^8 \, \text{m/s})}{80 \times 10^3 \times 1.6 \times 10^{-19} \, \text{J}} \] After calculating, we find: \[ \lambda \approx 0.155 \, \text{Å} \] 7. **Conclusion**: The X-rays emitted by the tube contain a continuous X-ray spectrum with a minimum wavelength of approximately \( 0.155 \, \text{Å} \).

To solve the problem, we need to analyze the situation where electrons with energy of 80 keV are incident on a tungsten target, and we need to determine the characteristics of the X-rays emitted from this interaction. ### Step-by-Step Solution: 1. **Identify the Energy of Incident Electrons**: The energy of the incident electrons is given as \( E = 80 \, \text{keV} \). 2. **Identify the Binding Energy of K-shell Electrons**: ...
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DC PANDEY ENGLISH-MODERN PHYSICS - 1-Level 2 Subjective
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