Intensity and frequency of incident light both are doubled.
Then, what is the effect on stopping potential and saturation current.

Explanation

To solve the problem regarding the effects of doubling the intensity and frequency of incident light on stopping potential and saturation current, we can break it down into a series of steps:

### Step 1: Understand the relationship between frequency and energy of photons
The energy of a photon is given by the equation:
\[ E = h \nu \]
where \( E \) is the energy, \( h \) is Planck's constant, and \( \nu \) is the frequency of the light.

### Step 2: Analyze the effect of doubling the frequency
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