Home
Class 12
PHYSICS
An alpha-particle and a proton are acce...

An `alpha`-particle and a proton are accelerated from rest by the same potential . Find the ratio of their de Broglie wavelengths .

Text Solution

Verified by Experts

The correct Answer is:
B

`lambda = (h)/(sqrt(2qVm)) rArr lambda prop (1)/(sqrt(qm))`
`(lambda_p)/(lambda_d) = sqrt((qm)_d)/((qm)_p) = sqrt((1xx2/(1xx1)) = sqrt2`
Promotional Banner

Topper's Solved these Questions

  • MODERN PHYSICS - 1

    DC PANDEY ENGLISH|Exercise Exercise 33.2|12 Videos
  • MODERN PHYSICS - 1

    DC PANDEY ENGLISH|Exercise Exercise 33.3|6 Videos
  • MODERN PHYSICS - 1

    DC PANDEY ENGLISH|Exercise Miscellaneous Examples|9 Videos
  • MODERN PHYSICS

    DC PANDEY ENGLISH|Exercise Integer Type Questions|17 Videos
  • MODERN PHYSICS - 2

    DC PANDEY ENGLISH|Exercise Level 2 Subjective|10 Videos

Similar Questions

Explore conceptually related problems

An alpha -particle and a proton are accelerated from rest through the same potential difference V. Find the ratio of de-Broglie wavelength associated with them.

Mention the significance of Davisson-Germer experiment. An alpha -particle and a proton are accelerated from rest through the same potential difference V . Find the ratio of de-Broglie wavelengths associated with them.

A proton and deuteron are accelerated by same potential difference.Find the ratio of their de-Broglie wavelengths.

An alpha particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de-Broglie wavelengths are lambda_a and lambda_p respectively. The ratio (lambda_p)/(lambda_a) , to the nearest integer, is.

An a- particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de-Broglie wavelengths are lambda_a and lambda_p respectively. The ratio (lambda_p)/(lambda_a) , to the nearest integer, is.

An electron and a proton are accelerated through the same potential difference. The ratio of their de broglic wavelengths will be

If an alpha particle and a proton are accelerated from rest by a potential difference of 1MeV, then the ratio of their kinetic energies will be

An electron of mass m_e and a proton of mass m_p are accelerated through the same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is

A positron and a proton are accelerated by the same accelerating potential. Then the ratio of the associated wavelengths of the positron and the proton will be [M=Mass of proton, m=Mass of positron]

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is