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An electron has a de Broglie wavelength ...

An electron has a de Broglie wavelength of `2.80xx10^(-10)` m. Determine (a) the magnitude of its momentum,
(b) its kinetci energy(in joule and in electron volt).

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The correct Answer is:
A, B, C, D
(a) `lambda rArr (h)/(P) rArr p=(h)/(lambda)`
(b) `lambda = (lambda)/(sqrt2km) rArr K = (h^2)/(2m lambda^2).`
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