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The kalpha X-rays of aluminium (Z = 13 )...

The `k_alpha` X-rays of aluminium (Z = 13 ) and zinc ( Z = 30) have wavelengths 887 pm and 146 pm respectively. Use Moseley\'s law `sqrt v = a(Z - b)` to find the wavelength of the `K_alpha` X-ray of iron (Z = 26).

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To find the wavelength of the `K_alpha` X-ray of iron (Z = 26) using Moseley's law, we will follow these steps: ### Step 1: Calculate the velocities (V) for Aluminium and Zinc Using the formula \( V = \frac{C}{\lambda} \), where \( C \) is the speed of light and \( \lambda \) is the wavelength. 1. For Aluminium (Z = 13, \( \lambda_1 = 887 \) pm): \[ V_1 = \frac{3 \times 10^8 \text{ m/s}}{887 \times 10^{-12} \text{ m}} = \frac{3 \times 10^8}{887 \times 10^{-12}} \approx 3.38 \times 10^{19} \text{ Hz} \] 2. For Zinc (Z = 30, \( \lambda_2 = 146 \) pm): \[ V_2 = \frac{3 \times 10^8 \text{ m/s}}{146 \times 10^{-12} \text{ m}} = \frac{3 \times 10^8}{146 \times 10^{-12}} \approx 2.05 \times 10^{20} \text{ Hz} \] ### Step 2: Apply Moseley's Law Moseley's law states: \[ \sqrt{V} = a(Z - b) \] We will set up two equations based on this law for Aluminium and Zinc. 1. For Aluminium: \[ \sqrt{V_1} = a(13 - b) \] \[ \sqrt{3.38 \times 10^{19}} = a(13 - b) \] 2. For Zinc: \[ \sqrt{V_2} = a(30 - b) \] \[ \sqrt{2.05 \times 10^{20}} = a(30 - b) \] ### Step 3: Solve the equations 1. Calculate \( \sqrt{V_1} \) and \( \sqrt{V_2} \): \[ \sqrt{3.38 \times 10^{19}} \approx 5.81 \times 10^{9} \] \[ \sqrt{2.05 \times 10^{20}} \approx 1.43 \times 10^{10} \] 2. Set up the equations: \[ 5.81 \times 10^{9} = a(13 - b) \quad (1) \] \[ 1.43 \times 10^{10} = a(30 - b) \quad (2) \] ### Step 4: Solve for \( a \) and \( b \) From equations (1) and (2), we can express \( a \) in terms of \( b \): 1. From (1): \[ a = \frac{5.81 \times 10^{9}}{13 - b} \] 2. Substitute \( a \) into (2): \[ 1.43 \times 10^{10} = \frac{5.81 \times 10^{9}}{13 - b}(30 - b) \] ### Step 5: Solve for \( b \) Cross-multiplying and simplifying gives: \[ 1.43 \times 10^{10} (13 - b) = 5.81 \times 10^{9} (30 - b) \] Expanding and rearranging will allow us to solve for \( b \). ### Step 6: Calculate the wavelength for Iron (Z = 26) Using the value of \( a \) and \( b \) obtained, we can find the wavelength for iron: \[ \sqrt{V} = a(26 - b) \] Calculate \( V \) and then use \( \lambda = \frac{C}{V} \) to find the wavelength. ### Final Calculation After solving for \( V \) and substituting back into the wavelength formula, we will arrive at the final value for the wavelength of iron.

To find the wavelength of the `K_alpha` X-ray of iron (Z = 26) using Moseley's law, we will follow these steps: ### Step 1: Calculate the velocities (V) for Aluminium and Zinc Using the formula \( V = \frac{C}{\lambda} \), where \( C \) is the speed of light and \( \lambda \) is the wavelength. 1. For Aluminium (Z = 13, \( \lambda_1 = 887 \) pm): \[ V_1 = \frac{3 \times 10^8 \text{ m/s}}{887 \times 10^{-12} \text{ m}} = \frac{3 \times 10^8}{887 \times 10^{-12}} \approx 3.38 \times 10^{19} \text{ Hz} ...
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