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In Bohr model of the hydrogen atom, let ...

In Bohr model of the hydrogen atom, let R,v and E represent the radius of the orbit, speed of the electron and the total energy respectively. Which of the following quantities are directly proportional to the quantum number n?

A

vR

B

RE

C

v/E

D

R/E

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the relationships between the radius \( r \), speed \( v \), and total energy \( E \) of the electron in a hydrogen atom according to the Bohr model, and how they relate to the principal quantum number \( n \). ### Step-by-step Solution: 1. **Determine the Formula for Speed \( v \)**: The speed of the electron in the nth orbit of a hydrogen atom is given by: \[ v = \frac{e^2}{2 \epsilon_0 h n} \] From this formula, we can see that: \[ v \propto \frac{1}{n} \] This means that speed \( v \) is inversely proportional to the principal quantum number \( n \). **Hint**: Remember that the speed decreases as the quantum number increases. 2. **Determine the Formula for Radius \( r \)**: The radius of the nth orbit is given by: \[ r = \frac{h^2 \epsilon_0}{\pi m e^2} n^2 \] From this formula, we can see that: \[ r \propto n^2 \] This indicates that the radius \( r \) is directly proportional to the square of the principal quantum number \( n \). **Hint**: The radius increases with the square of the quantum number. 3. **Determine the Formula for Total Energy \( E \)**: The total energy of the electron in the nth orbit is given by: \[ E = -\frac{m e^4}{8 \epsilon_0^2 h^2} \frac{1}{n^2} \] From this, we can see that: \[ E \propto \frac{1}{n^2} \] This means that the total energy \( E \) is inversely proportional to the square of the principal quantum number \( n \). **Hint**: The energy becomes less negative (increases) as \( n \) increases. 4. **Analyze the Given Quantities**: Now we need to analyze the quantities \( vr \), \( re \), \( \frac{v}{E} \), and \( \frac{r}{E} \) to see which are directly proportional to \( n \). - **For \( vr \)**: \[ vr = v \cdot r = \left(\frac{1}{n}\right) \cdot (n^2) = n \] Thus, \( vr \) is directly proportional to \( n \). - **For \( re \)**: \[ re = r \cdot E = (n^2) \cdot \left(-\frac{1}{n^2}\right) = -1 \] Thus, \( re \) is a constant and not proportional to \( n \). - **For \( \frac{v}{E} \)**: \[ \frac{v}{E} = \frac{\left(\frac{1}{n}\right)}{\left(-\frac{1}{n^2}\right)} = -n \] Thus, \( \frac{v}{E} \) is directly proportional to \( n \). - **For \( \frac{r}{E} \)**: \[ \frac{r}{E} = \frac{(n^2)}{\left(-\frac{1}{n^2}\right)} = -n^4 \] Thus, \( \frac{r}{E} \) is directly proportional to \( n^4 \), but not directly proportional to \( n \). ### Conclusion: The quantities that are directly proportional to the principal quantum number \( n \) are: - \( vr \) - \( \frac{v}{E} \) ### Final Answer: The correct options are \( vr \) and \( \frac{v}{E} \).

To solve the problem, we need to analyze the relationships between the radius \( r \), speed \( v \), and total energy \( E \) of the electron in a hydrogen atom according to the Bohr model, and how they relate to the principal quantum number \( n \). ### Step-by-step Solution: 1. **Determine the Formula for Speed \( v \)**: The speed of the electron in the nth orbit of a hydrogen atom is given by: \[ v = \frac{e^2}{2 \epsilon_0 h n} ...
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