Home
Class 12
PHYSICS
Find an expression fot the magneitc dip...

Find an expression fot the magneitc dipole moment and magnetic field induction at the centre of Bohr'r hypothetical hydrogen atom in the n th orbit of the electron in terms of universal constant.

Text Solution

AI Generated Solution

The correct Answer is:
To find the expressions for the magnetic dipole moment and the magnetic field induction at the center of Bohr's hypothetical hydrogen atom in the nth orbit of the electron, we can follow these steps: ### Step 1: Magnetic Dipole Moment Calculation 1. **Formula for Magnetic Dipole Moment (μ)**: The magnetic dipole moment for an electron in the nth orbit can be expressed as: \[ \mu_n = I \cdot A \] where \(I\) is the current and \(A\) is the area of the orbit. 2. **Current (I) in nth Orbit**: The current \(I\) can be defined as the charge \(Q\) passing through the orbit per unit time. The time period \(T_n\) for one complete revolution of the electron in the nth orbit is given by: \[ I = \frac{Q}{T_n} \] 3. **Area (A) of nth Orbit**: The area \(A\) of the circular orbit is: \[ A = \pi R_n^2 \] where \(R_n\) is the radius of the nth orbit. 4. **Substituting for Current and Area**: Therefore, the magnetic dipole moment can be rewritten as: \[ \mu_n = \left(\frac{Q}{T_n}\right) \cdot (\pi R_n^2) \] 5. **Finding the Time Period (T_n)**: The time period \(T_n\) can be expressed in terms of angular velocity (\(\omega_n\)): \[ T_n = \frac{2\pi}{\omega_n} \] Thus, we can substitute this into the current expression: \[ I = \frac{Q \cdot \omega_n}{2\pi} \] 6. **Final Expression for Magnetic Dipole Moment**: Substituting \(I\) back into the expression for \(\mu_n\): \[ \mu_n = \frac{Q \cdot \omega_n}{2\pi} \cdot \pi R_n^2 = \frac{Q \cdot \omega_n \cdot R_n^2}{2} \] 7. **Expressing in Terms of Constants**: Using the relationships \(V_n = \frac{Z e^2}{n}\) and \(R_n = \frac{R_0 n^2}{Z}\), we can simplify further: \[ \mu_n = \frac{Q \cdot V_n \cdot R_n}{2} \] This leads to: \[ \mu_n = \frac{Q \cdot V_0 \cdot R_0}{2} \cdot n \] where \(V_0\) and \(R_0\) are constants. ### Step 2: Magnetic Field Induction Calculation 1. **Formula for Magnetic Field (B)**: The magnetic field induction at the center of the atom due to the revolving electron is given by: \[ B_n = \frac{\mu_0 I_n}{2 R_n} \] 2. **Substituting for Current (I_n)**: Using the expression for current \(I_n\): \[ B_n = \frac{\mu_0 \cdot \frac{Q}{T_n}}{2 R_n} \] 3. **Substituting for Time Period (T_n)**: Substitute \(T_n\) in the expression: \[ B_n = \frac{\mu_0 \cdot Q \cdot \omega_n}{4 \pi R_n} \] 4. **Final Expression for Magnetic Field**: Substituting \(R_n\) and simplifying: \[ B_n = \frac{\mu_0 Q V_0 Z^3}{4 \pi R_0^2 n^5} \] This can be expressed as: \[ B_n = B_0 \frac{Z^3}{n^5} \] where \(B_0\) is a constant. ### Summary of Results - **Magnetic Dipole Moment**: \[ \mu_n = \frac{Q V_0 R_0}{2} n \] - **Magnetic Field Induction**: \[ B_n = B_0 \frac{Z^3}{n^5} \]

To find the expressions for the magnetic dipole moment and the magnetic field induction at the center of Bohr's hypothetical hydrogen atom in the nth orbit of the electron, we can follow these steps: ### Step 1: Magnetic Dipole Moment Calculation 1. **Formula for Magnetic Dipole Moment (μ)**: The magnetic dipole moment for an electron in the nth orbit can be expressed as: \[ \mu_n = I \cdot A ...
Promotional Banner

Topper's Solved these Questions

  • MODERN PHYSICS - 1

    DC PANDEY ENGLISH|Exercise Level 2 Passage 4|1 Videos
  • MODERN PHYSICS

    DC PANDEY ENGLISH|Exercise Integer Type Questions|17 Videos
  • MODERN PHYSICS - 2

    DC PANDEY ENGLISH|Exercise Level 2 Subjective|10 Videos

Similar Questions

Explore conceptually related problems

Find an expression for the magnetic dipole moment and magnetic field induction at the center of Bohr's hypothetical hydrogen atom in the nth orbit of the electron in terms of universal constant.

Deduce an expression for the magnetic dipole moment of an electron orbiting around the central nucleus.

The magnetic field induction produced at the centre of orbit due to an electron revolving in n^(th) orbit of hydrogen atom is proportional to

The ratio of magnetic dipole moment of an electron of charge e and mass m in the Bohr orbit in hydrogen to the angular momentum of the electron in the orbit is:

According to Bohr model, magnetic field at the centre (at the nucleus) of a hydrogen atom due to the motion of the electron in nth orbit is proportional to 1//n^(x) , find the value of x

Magnetic field at the center (at nucleus) of the hydrogen like atom ("atomic number" = z) due to the motion of electron in nth orbit is proporional to

Magnetic moment of an electron in nth orbit of hydrogen atom is

Magnetic moment of an electron in nth orbit of hydrogen atom is

Calculate the value of X if magnetic field strength at the centre of a hydrogen atom caused by an electron moving along the first Bohr orbits is (X)/(2)T .

An electron in the ground state of hydrogen atom is revolving in anticlock-wise direction in a circular orbit of radius R . (i) Obtain an experssion for the orbital magnetic dipole moment of the electron. (ii) The atom is placed in a uniform magnetic induction vec(B) such that the plane - normal of the electron - orbit makes an angle of 30^(@) with the magnetic induction . Find the torque experienced by the orbiting electron.

DC PANDEY ENGLISH-MODERN PHYSICS - 1-Level 2 Subjective
  1. (a) A gas of hydrogen atoms is their ground state is bombarded by ele...

    Text Solution

    |

  2. A source emits monochromatic light of frequency 5.5xx10^(14) Hzat a ra...

    Text Solution

    |

  3. The hydrogen atom in its ground state is excited by means of monochrom...

    Text Solution

    |

  4. Electrons in hydrogen like atom (Z= 3) make transition from the fifth ...

    Text Solution

    |

  5. Find an expression fot the magneitc dipole moment and magnetic field...

    Text Solution

    |

  6. An electron and a proton are seperated by a large distance and the ele...

    Text Solution

    |

  7. Hydrogen gas in the atomic state is excited to an energy level such th...

    Text Solution

    |

  8. A gas of hydrogen - like atoms can absorb radiations of 698 eV. Conseq...

    Text Solution

    |

  9. A photon with energy of 4.9 eV ejects photoelectrons from tungsten. Wh...

    Text Solution

    |

  10. For a certain hypothetical one electron atom, the wavelength (in Å) fo...

    Text Solution

    |

  11. A photocell is operating in saturation mode with a photocurrent 4.8 mA...

    Text Solution

    |

  12. The photons from the Balmer series in Hydrogen spectrum having wavele...

    Text Solution

    |

  13. Assume that the de Broglie wave associated with an electron can from a...

    Text Solution

    |

  14. The nagative muon has charge equal to that of an electron but a mass t...

    Text Solution

    |

  15. Assume a hypothetical hydrogen atom in which the potential energy betw...

    Text Solution

    |

  16. An electron is orbiting is a circular orbit of radius r under the infl...

    Text Solution

    |

  17. A mixture of hydrogen atoms (in their ground state) and hydrogen like...

    Text Solution

    |

  18. When a surface is irradiated with light of wavelength 4950 Å, a photo...

    Text Solution

    |

  19. In an experiment on photoelectric effect of light wavelength 400 nm i...

    Text Solution

    |

  20. A light beam of wavelength 400 nm is incident on a metal of work- func...

    Text Solution

    |