In a neutron induced fission of 92U^235 ...

In a neutron induced fission of `_92U^235` nucleus, usable energy of 185 MeV is released. If `_92U^235` reactor is continuously operating it at a power level of 100 MW power, how long will it take for 1 kg of uranium to be consumed in this reactor?

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The correct Answer is:

A, D

Number of nuclei in 1kg of uranium,
`N=(1/235)(6.02xx10^26)`
Now, `(1/235)(6.02xx10^26)(185xx1.6xx10^-13)`
`=(100xx10^6)t`
`:.` `t=7.58xx10^5s`
`=(7.58xx10^5)/(60xx60xx24)day`
`=8.78 days`

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