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Consider the following nuclear reaction,...

Consider the following nuclear reaction, `X^200rarrA^110+B^90+En ergy`
If the binding energy per nucleon for X, A and B are 7.4 MeV, 8.2 MeV and 8.2 MeV respectively, the energy released will be

A

(a) 900 MeV

B

(b) 110 MeV

C

(c) 200 MeV

D

(d) 160 MeV

Text Solution

AI Generated Solution

The correct Answer is:
To find the energy released in the nuclear reaction \( X^{200} \rightarrow A^{110} + B^{90} + \text{Energy} \), we will follow these steps: ### Step 1: Identify the binding energy per nucleon We are given the binding energy per nucleon for the following nuclei: - For nucleus \( X \): 7.4 MeV - For nucleus \( A \): 8.2 MeV - For nucleus \( B \): 8.2 MeV ### Step 2: Calculate the total binding energy of the initial nucleus \( X \) The total number of nucleons in \( X \) is 200. Therefore, the total binding energy of \( X \) can be calculated as: \[ \text{Total Binding Energy of } X = \text{Binding Energy per Nucleon} \times \text{Number of Nucleons} \] \[ = 7.4 \, \text{MeV/nucleon} \times 200 \, \text{nucleons} = 1480 \, \text{MeV} \] ### Step 3: Calculate the total binding energy of the final products \( A \) and \( B \) - For nucleus \( A \) (110 nucleons): \[ \text{Total Binding Energy of } A = 8.2 \, \text{MeV/nucleon} \times 110 \, \text{nucleons} = 902 \, \text{MeV} \] - For nucleus \( B \) (90 nucleons): \[ \text{Total Binding Energy of } B = 8.2 \, \text{MeV/nucleon} \times 90 \, \text{nucleons} = 738 \, \text{MeV} \] ### Step 4: Calculate the total binding energy of the final products Now, we add the binding energies of \( A \) and \( B \): \[ \text{Total Binding Energy of Final Products} = 902 \, \text{MeV} + 738 \, \text{MeV} = 1640 \, \text{MeV} \] ### Step 5: Calculate the energy released in the reaction The energy released in the reaction is given by the difference in binding energy between the final products and the initial nucleus: \[ \text{Energy Released} = \text{Total Binding Energy of Final Products} - \text{Total Binding Energy of } X \] \[ = 1640 \, \text{MeV} - 1480 \, \text{MeV} = 160 \, \text{MeV} \] ### Final Answer The energy released in the reaction is \( 160 \, \text{MeV} \). ---

To find the energy released in the nuclear reaction \( X^{200} \rightarrow A^{110} + B^{90} + \text{Energy} \), we will follow these steps: ### Step 1: Identify the binding energy per nucleon We are given the binding energy per nucleon for the following nuclei: - For nucleus \( X \): 7.4 MeV - For nucleus \( A \): 8.2 MeV - For nucleus \( B \): 8.2 MeV ...
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