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The external and internal diameters of a...

The external and internal diameters of a hollow cylinder are measured to be `(4.23+-0.01)` cm and `(3.89+-0.01)`cm. The thickne of the wall of the cylinder is

A

`(0.34+-0.02)cm`

B

`(0.17+-0.02)cm`

C

`(0.17+-0.01)cm`

D

`(0.34+-0.01)cm`

Text Solution

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The correct Answer is:
To find the thickness of the wall of a hollow cylinder given the external and internal diameters, we can follow these steps: ### Step 1: Write down the given values - External diameter (De) = \(4.23 \pm 0.01\) cm - Internal diameter (Di) = \(3.89 \pm 0.01\) cm ### Step 2: Calculate the external radius (Re) The external radius (Re) is half of the external diameter: \[ Re = \frac{De}{2} = \frac{4.23 \, \text{cm}}{2} = 2.115 \, \text{cm} \] To find the uncertainty in the radius, we divide the uncertainty in the diameter by 2: \[ \Delta Re = \frac{0.01 \, \text{cm}}{2} = 0.005 \, \text{cm} \] Thus, the external radius is: \[ Re = 2.115 \pm 0.005 \, \text{cm \] ### Step 3: Calculate the internal radius (Ri) The internal radius (Ri) is half of the internal diameter: \[ Ri = \frac{Di}{2} = \frac{3.89 \, \text{cm}}{2} = 1.945 \, \text{cm} \] Similarly, the uncertainty in the internal radius is: \[ \Delta Ri = \frac{0.01 \, \text{cm}}{2} = 0.005 \, \text{cm} \] Thus, the internal radius is: \[ Ri = 1.945 \pm 0.005 \, \text{cm} \] ### Step 4: Calculate the thickness of the wall (t) The thickness of the wall (t) is the difference between the external radius and the internal radius: \[ t = Re - Ri = (2.115 \pm 0.005) - (1.945 \pm 0.005) \] Calculating the difference: \[ t = 2.115 - 1.945 = 0.17 \, \text{cm} \] ### Step 5: Calculate the uncertainty in thickness To find the uncertainty in thickness, we add the uncertainties of the external and internal radii: \[ \Delta t = \Delta Re + \Delta Ri = 0.005 + 0.005 = 0.01 \, \text{cm} \] ### Final Result Thus, the thickness of the wall of the cylinder is: \[ t = 0.17 \pm 0.01 \, \text{cm} \]
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