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The length of a rectangular plate is mea...

The length of a rectangular plate is measured by a meter scale and is found to be ` 10.0 cm`. Its width is measured by vernier callipers as `1.00 cm`. The least count of the meter scale and vernier calipers are `0.1 cm and 0.01 cm` respectively. Maximum permissibe error in area measurement is.

A

`+-0.2cm^(2)`

B

`+-0.1cm^(2)`

C

`+-0.3cm^(2)`

D

zero

Text Solution

AI Generated Solution

The correct Answer is:
To find the maximum permissible error in the area measurement of the rectangular plate, we will follow these steps: ### Step 1: Identify the given values - Length (L) = 10.0 cm - Width (W) = 1.00 cm - Least count of the meter scale (for length) = 0.1 cm - Least count of the vernier calipers (for width) = 0.01 cm ### Step 2: Determine the absolute errors - The absolute error in length (ΔL) is equal to the least count of the meter scale: \[ \Delta L = 0.1 \, \text{cm} \] - The absolute error in width (ΔW) is equal to the least count of the vernier calipers: \[ \Delta W = 0.01 \, \text{cm} \] ### Step 3: Calculate the area of the rectangle The area (A) of the rectangle is given by: \[ A = L \times W = 10.0 \, \text{cm} \times 1.00 \, \text{cm} = 10.0 \, \text{cm}^2 \] ### Step 4: Use the formula for the maximum permissible error in area The formula for the relative error in area (ΔA) is given by: \[ \frac{\Delta A}{A} = \frac{\Delta L}{L} + \frac{\Delta W}{W} \] Substituting the values, we get: \[ \frac{\Delta A}{10.0} = \frac{0.1}{10.0} + \frac{0.01}{1.00} \] ### Step 5: Calculate the individual terms Calculating each term: \[ \frac{\Delta L}{L} = \frac{0.1}{10.0} = 0.01 \] \[ \frac{\Delta W}{W} = \frac{0.01}{1.00} = 0.01 \] ### Step 6: Combine the relative errors Now, adding these two relative errors: \[ \frac{\Delta A}{10.0} = 0.01 + 0.01 = 0.02 \] ### Step 7: Calculate the maximum permissible error in area To find ΔA: \[ \Delta A = A \times \frac{\Delta A}{A} = 10.0 \, \text{cm}^2 \times 0.02 = 0.2 \, \text{cm}^2 \] ### Conclusion The maximum permissible error in the area measurement is: \[ \Delta A = 0.2 \, \text{cm}^2 \] ### Final Answer The maximum permissible error in area measurement is **0.2 cm²**. ---
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