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Locus of all the points in a plane on wh...

Locus of all the points in a plane on which the moment of inertia about all mutually parallel axes of a rigid body is same throughout is

A

a straight line

B

a circle

C

a parabola

D

an ellipse

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The correct Answer is:
To determine the locus of all points in a plane where the moment of inertia about all mutually parallel axes of a rigid body is the same, we can follow these steps: ### Step 1: Understand the Moment of Inertia The moment of inertia \( I \) of a rigid body about an axis is defined as: \[ I = \sum m_i r_i^2 \] where \( m_i \) is the mass of the individual particles and \( r_i \) is the distance from the axis of rotation. ### Step 2: Apply the Parallel Axis Theorem According to the parallel axis theorem, the moment of inertia about a parallel axis can be expressed as: \[ I = I_{cm} + Mh^2 \] where: - \( I_{cm} \) is the moment of inertia about the center of mass, - \( M \) is the total mass of the body, - \( h \) is the distance between the two parallel axes. ### Step 3: Analyze the Condition for Constant Moment of Inertia For the moment of inertia to remain constant for all parallel axes, the term \( Mh^2 \) must not change with different positions of the axis. This implies that the distance \( h \) must be constant. ### Step 4: Determine the Locus of Points If \( h \) is constant, then the locus of points that maintain this constant distance from a fixed point (the center of mass) forms a circle. This is because all points on a circle are equidistant from the center. ### Conclusion Thus, the locus of all points in a plane where the moment of inertia about all mutually parallel axes of a rigid body is the same is a **circle**. ### Final Answer The correct option is a **circle**. ---
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