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A particle moves in a circle with consta...

A particle moves in a circle with constant angular velocity `omega` about a point P on its circumference. The angular velocity of the particle about the centre C of the circle is

A

`2omega`

B

`(omega)/(2)`

C

`omega`

D

Not constant

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The correct Answer is:
To solve the problem, we need to find the angular velocity of a particle moving in a circle with constant angular velocity \( \omega \) about a point \( P \) on its circumference, with respect to the center \( C \) of the circle. ### Step-by-Step Solution: 1. **Understanding the Motion**: - The particle is moving in a circular path around point \( P \) on the circumference of the circle. - Let's denote the angle covered by the particle as \( \theta \) when it moves from position \( A \) to position \( B \) around point \( P \). 2. **Relating Angles**: - According to the properties of circular motion, if the angle covered by the point \( P \) (the center of rotation for the particle) is \( \theta \), then the angle \( \phi \) covered by the particle with respect to the center \( C \) of the circle will be \( 2\theta \). - This is because the angle subtended at the center of a circle is always twice the angle subtended at any point on the circumference. 3. **Angular Velocity Definition**: - Angular velocity \( \omega \) is defined as the rate of change of angular displacement with respect to time. Mathematically, it is given by: \[ \omega = \frac{d\theta}{dt} \] 4. **Calculating Angular Velocity about Center \( C \)**: - Since the angle \( \phi \) covered by the particle with respect to center \( C \) is \( 2\theta \), we can express the angular velocity with respect to center \( C \) as: \[ \omega_C = \frac{d\phi}{dt} = \frac{d(2\theta)}{dt} = 2\frac{d\theta}{dt} \] - Substituting \( \frac{d\theta}{dt} \) with \( \omega \): \[ \omega_C = 2\omega \] 5. **Conclusion**: - Therefore, the angular velocity of the particle about the center \( C \) of the circle is \( 2\omega \). ### Final Answer: The angular velocity of the particle about the center \( C \) of the circle is \( 2\omega \). ---
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