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A rod of length l is given two velocitie...

A rod of length l is given two velocities `v_(1)` and `v_(2)` in opposite directions at its two ends at right angles to the length. The distance of the instantaneous axis of rotation from `v_(1)` is

A

zero

B

`(v_(1))/(v_(1)+v_(2))l`

C

`(v_(2)l)/(v_(1)+v_(2))`

D

`(l)/(2)`

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The correct Answer is:
To solve the problem of finding the distance of the instantaneous axis of rotation from \( v_1 \) for a rod of length \( l \ given two velocities \( v_1 \) and \( v_2 \) at its ends in opposite directions, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Setup**: - We have a rod of length \( l \). - The left end of the rod has a velocity \( v_1 \) and the right end has a velocity \( v_2 \). - The velocities are directed perpendicular to the length of the rod and in opposite directions. 2. **Define the Instantaneous Axis of Rotation**: - Let the distance from the point where \( v_1 \) is applied to the instantaneous axis of rotation be \( x \). - Consequently, the distance from the point where \( v_2 \) is applied to the instantaneous axis of rotation will be \( l - x \). 3. **Relate Angular Velocities**: - The angular velocity \( \omega \) about the instantaneous axis of rotation can be expressed for both ends of the rod: - For the end with velocity \( v_1 \): \[ \omega = \frac{v_1}{x} \] - For the end with velocity \( v_2 \): \[ \omega = \frac{v_2}{l - x} \] 4. **Set the Angular Velocities Equal**: - Since both expressions represent the same angular velocity \( \omega \), we can set them equal to each other: \[ \frac{v_1}{x} = \frac{v_2}{l - x} \] 5. **Cross-Multiply to Solve for \( x \)**: - Cross-multiplying gives: \[ v_1 (l - x) = v_2 x \] - Expanding the left side: \[ v_1 l - v_1 x = v_2 x \] 6. **Combine Like Terms**: - Rearranging the equation: \[ v_1 l = v_1 x + v_2 x \] - Factoring out \( x \): \[ v_1 l = x (v_1 + v_2) \] 7. **Solve for \( x \)**: - Finally, solve for \( x \): \[ x = \frac{v_1 l}{v_1 + v_2} \] ### Conclusion: The distance of the instantaneous axis of rotation from \( v_1 \) is given by: \[ x = \frac{v_1 l}{v_1 + v_2} \]
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