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In a projectile motion let t(OA)=t(1) an...

In a projectile motion let `t_(OA)=t_(1)` and `t_(AB)=t_(2)`.The horizontal displacement from `O` to `A` is `R_(1)` and from `A` to `B` is `R_(2)`.Maximum height is `H` and time of flight is `T`.If air drag is to be considered, then choose the correct alternative(s).

A

`t_(1)` will decrease while `t_(2)` will increase

B

`H` will increase

C

`R_(1)` will decrease while `R_(2)` will increase

D

`T` may increased or decrease

Text Solution

Verified by Experts

The correct Answer is:
A, D
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Knowledge Check

  • The relation between the time of flight of projectile T_(f) and the time to reach the maximum height t_(m) is

    A
    `T_(f) = 2t_(m)`
    B
    `T_(f) = t_(m)`
    C
    `T_(f) = (t_(m))/(2)`
    D
    `T_(f) = sqrt(2)(t_(m))`

  • Two particls are projected in air with speed u at angles theta_(1) and theta_(2) (both acute) to the horizontal, respectively. If the height reached by the first particle is greater than that of the second, then which one of the following is correct? where T_(1) and T_(2) are the time of flight.

    A
    `theta_(1) gt theta_(2)`
    B
    `theta_(1) = theta_(2)`
    C
    `T_(1) lt T_(2)`
    D
    `T_(1) = T_(2)`

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