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An object is projected with a velocitiy ...

An object is projected with a velocitiy of `20m//s` making an angle of `45^(@)` with horizontal. The equation for trajectory is `h=Ax-Bx^(2)` where `h` is height `x` is horizontal distance. `A` and `B` are constants. The ratio `A.B` is `x/0.1`. Find value of `x.(g=10m//s^(2))`

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