Home
Class 11
PHYSICS
A ball B of mass m is lying at rest on t...

A ball B of mass m is lying at rest on the top surface of a smooth horizontal table 5 m high. Another moovin ball A of same mass make an elastic colision with B slides off the table and strikes the floor at a horizonatal distance of 10 m from the table. Then select the correct alternatives (s). `[g=10m//s^(2)]`

A

The velocity of the ball A befor collisionis 5 m/s

B

The kinetic energy of the ball B at the time when it strikes yhe ground is (mx100) J

C

the velocity of the ball A before collision is 10 m/s

D

The kinetic energy of the ball B at the time when it strikes the ground is (50xm) J

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze the situation step by step. ### Step 1: Understanding the Problem We have two balls, A and B, both with mass \( m \). Ball B is at rest on a table that is 5 meters high. Ball A is moving and collides elastically with ball B, causing ball B to remain at rest and ball A to slide off the table. ### Step 2: Determine the Velocity of Ball A Before Collision Since the collision is elastic and both balls have the same mass, we can use the conservation of momentum and kinetic energy. After the collision, ball A will move with the same velocity that ball B had before the collision. Using the conservation of energy: \[ \frac{1}{2} m v^2 = mgh \] Where: - \( h = 5 \, \text{m} \) - \( g = 10 \, \text{m/s}^2 \) Rearranging gives: \[ v^2 = 2gh \] Substituting the values: \[ v^2 = 2 \times 10 \times 5 = 100 \] Taking the square root: \[ v = \sqrt{100} = 10 \, \text{m/s} \] Thus, the velocity of ball A before the collision is \( 10 \, \text{m/s} \). ### Step 3: Analyzing the Motion of Ball A After Collision After the collision, ball A slides off the table horizontally. We need to find the time it takes for ball A to hit the ground. Using the formula for the time of free fall: \[ h = \frac{1}{2} g t^2 \] Substituting \( h = 5 \, \text{m} \) and \( g = 10 \, \text{m/s}^2 \): \[ 5 = \frac{1}{2} \times 10 \times t^2 \] This simplifies to: \[ 5 = 5t^2 \implies t^2 = 1 \implies t = 1 \, \text{s} \] ### Step 4: Finding the Horizontal Distance Now, we can calculate the horizontal distance traveled by ball A while it is falling. The horizontal distance \( d \) can be calculated using: \[ d = v \times t \] Where: - \( v = 10 \, \text{m/s} \) - \( t = 1 \, \text{s} \) Substituting the values: \[ d = 10 \times 1 = 10 \, \text{m} \] ### Step 5: Conclusion The horizontal distance from the table to where ball A strikes the ground is indeed \( 10 \, \text{m} \), which matches the information provided in the problem. ### Final Answers 1. The velocity of ball A before the collision is \( 10 \, \text{m/s} \). 2. The time taken for ball A to hit the ground is \( 1 \, \text{s} \). 3. The horizontal distance traveled by ball A is \( 10 \, \text{m} \).
Promotional Banner

Similar Questions

Explore conceptually related problems

A ball A collides elasticlly with an another identical bass B with velocity 10 m//s at an angle of 30^(@) from the line joining their centres C_(1) and C_(2) Select the correct alternative (s).

A uniform rod AB of mass 3m and length 2l is lying at rest on a smooth horizontal table with a smooth vertical axis through the end A. A particle of mass 2m moves with speed 2u across the table and strikes the rod at its mid-point C if the impact is perfectly elastic. Find the speed of the particle after impact if (a). It strikes rod normally, (b). Its path before impact was inclinded at 60^(@) to AC.

A ball of mass m=1kg strikes a smooth horizontal floor as shown in figure. The impulse exerted on the floor is

A uniform rod of length l and mass 2 m rests on a smooth horizontal table. A point mass m moving horizontally at right angles to the rod with velocity v collides with one end of the rod and sticks it. Then

A uniform rod of length l and mass 2 m rests on a smooth horizontal table. A point mass m moving horizontally at right angles to the rod with velocity v collides with one end of the rod and sticks it. Then

A ball rolls off the edge of a horizontal table top 4 m high. If it strikes the floor at a point 5 m horizontally away from the edge of the table, what was its speed at the instant it left the table?

A ball of mass 2kg is thrown with velocity 10m/s at an angle of 30°to the horizontal and another ball with the same mass is thrown at an angel of 60° to the horizontal with the same speed.The ratio will be their range will be

The sides of rectangular plate of mass 20 kg is 5 m x 4 m placed on a horizontal table. The pressure exerted by the block on the table is (Take g = 10 m/s^2 )

A ball of mass 4 kg moving on a smooth horizontal surface makes an elastic collision with another ball of mass m at rest in the line of motion of first ball. If after collision first ball moves in the same direction with one fourth of its velocity before collision, then mass of second ball is

A girl throws the ball with horizontal velocity 2m//s at the moment t=0 . The ball bounces once on the smooth floor and then lands into cup C . The coefficient of restitution for the collision is 0.8 . Select the correct alternative (g=10m//s^(2))