Home
Class 11
PHYSICS
A barometer tube reads 76 cm of mercury....

A barometer tube reads 76 cm of mercury. If the tube is gradually inclined at an angle of `60` with vertical, keeping the open end immersed in the mercury reservoir, the length of the mercury column will be

A

152 cm

B

76 cm

C

38 cm

D

`38 sqrt3 cm`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the length of the mercury column in an inclined barometer tube, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We have a barometer tube that reads 76 cm of mercury when vertical. When the tube is inclined at an angle of 60 degrees with the vertical, we need to find the new length of the mercury column. 2. **Identify the Variables**: - Let \( S_v \) = height of the mercury column in the vertical tube = 76 cm. - Let \( S_i \) = height of the mercury column in the inclined tube. - Let \( H \) = vertical height of the mercury column when inclined. - Angle of inclination \( \theta = 60^\circ \). 3. **Use the Relationship Between Heights**: - In the vertical tube, the pressure is given by the formula \( P = \rho g h \), where \( h \) is the vertical height of the mercury column. - For the inclined tube, the vertical height \( H \) can be related to the inclined length \( S_i \) using trigonometry: \[ H = S_i \cos(\theta) \] - Thus, we can rearrange this to find \( S_i \): \[ S_i = \frac{H}{\cos(\theta)} \] 4. **Set Up the Pressure Equality**: - The pressure exerted by the mercury column must be equal in both cases: \[ \rho g H = \rho g S_v \] - Since \( \rho g \) cancels out, we have: \[ H = S_v \] - Therefore, \( H = 76 \, \text{cm} \). 5. **Calculate \( S_i \)**: - Substitute \( H \) into the equation for \( S_i \): \[ S_i = \frac{H}{\cos(60^\circ)} \] - We know that \( \cos(60^\circ) = \frac{1}{2} \): \[ S_i = \frac{76 \, \text{cm}}{\frac{1}{2}} = 76 \, \text{cm} \times 2 = 152 \, \text{cm} \] 6. **Conclusion**: - The length of the mercury column when the tube is inclined at 60 degrees is \( S_i = 152 \, \text{cm} \). ### Final Answer: The length of the mercury column in the inclined barometer tube is **152 cm**.
Promotional Banner

Topper's Solved these Questions

  • PROPERTIES OF MATTER

    DC PANDEY ENGLISH|Exercise JEE Advanced|57 Videos
  • PROPERTIES OF MATTER

    DC PANDEY ENGLISH|Exercise More than one option is correct|21 Videos
  • PROJECTILE MOTION

    DC PANDEY ENGLISH|Exercise Level - 2 Subjective|10 Videos
  • RAY OPTICS

    DC PANDEY ENGLISH|Exercise Integer type q.|14 Videos

Similar Questions

Explore conceptually related problems

A barometer tube reads 76 cm of Hg. If tube is : gradually inclined at an angle of 60^(@) with vertical, keeping the open end in the mercury reservoir, the length of mercury column will be

A barometer tube reads 76 cm of mercury. If the tube is gradually inclined keeping the open end immersed in the mercury reservoir, will the length of mercury column be 76 cm, more than 76 cm or less than 76 cm?

Water rises in a capillary tube to a height 4 cm. If the tube is inclined at an angle of 45^(@) with the vertical , find the position of the water in the tube.

If above tube is placed vertically with the open and upward then find the length of the air column.

If the above tube is kept in vertical position by how much length the mercury column descends ?

Water rises in a vertical capillary tube up to a height of 2.0 cm. If the tube is inclined at an angle of 60^@ with the vertical, then up to what length the water will rise in the tube ?

Air is trapped in a horizontal glass tube by 36 cm mercury column as shown below : If the tube is held vertical keeping the open end up, lengh of air column shrink to 19 cm. What is the lengh (in cm) by which the mercury column shifts down?

A column of mercury is in the middle of horizontal tube of uniform cross section closed at both ends. The pressure of the enclosed air column on either side of the mercury is 75 cm of mercury column. When the tuve is placed vertical the length air below the mercury column is (3)/(5) th of that above it. if length of mercury column is 10n cm. find n.

A thin tube of uniform cross-section is sealed at both ends. It lies horizontally, the middle 5 cm containing mercury and the two equal end containing air at the same pressure P. When the tube is held at an angle of 60^@ with the vetical direction, the length of the air column above and below the mercury column are 46 cm and 44.5 cm respectively. Calculate the pressure P in centimeters of mercury. (The temperature of the system is kept at 30^@C ).