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A balloon with mass m is descending down...

A balloon with mass `m` is descending down with an acceleration a `(where altg)` . How much mass should be removed from it so that it starts moving up with an acceleration a?

A

`(2M(g))/(a)`

B

`(M(g +a))/(g)`

C

`(Mg)/(g + a)`

D

`(2Ma)/(g + a)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how much mass should be removed from a descending balloon so that it starts moving upwards with a specified acceleration, we can follow these steps: ### Step 1: Analyze the Forces Acting on the Balloon The balloon has a mass `m` and is descending with an acceleration `a`, where `a < g` (g is the acceleration due to gravity). The forces acting on the balloon are: - The weight of the balloon, which is `W = mg` (downward). - The buoyant force `F` (upward). ### Step 2: Set Up the Equation for Downward Motion Since the balloon is descending with an acceleration `a`, we can apply Newton's second law: \[ mg - F = ma \] Rearranging gives us: \[ F = mg - ma \] This is our **Equation 1**. ### Step 3: Analyze the Forces When Mass is Removed Let’s denote the mass that needs to be removed as `m'`. After removing this mass, the new mass of the balloon becomes `m - m'`. We want the balloon to ascend with the same acceleration `a`. ### Step 4: Set Up the Equation for Upward Motion For the balloon to move upwards with an acceleration `a`, we can write: \[ F - (m - m')g = (m - m')a \] Rearranging gives us: \[ F = (m - m')g + (m - m')a \] This is our **Equation 2**. ### Step 5: Substitute Equation 1 into Equation 2 From **Equation 1**, we know that: \[ F = mg - ma \] Now we substitute this expression for `F` into **Equation 2**: \[ mg - ma = (m - m')g + (m - m')a \] ### Step 6: Expand and Rearrange the Equation Expanding the right side: \[ mg - ma = mg - m'g + ma - m'a \] Now, we can cancel `mg` from both sides: \[ -ma = -m'g + ma - m'a \] Rearranging gives: \[ -ma - ma = -m'g - m'a \] This simplifies to: \[ -2ma = -m'g - m'a \] ### Step 7: Factor Out m' Rearranging gives: \[ 2ma = m'(g + a) \] Now, we can solve for `m'`: \[ m' = \frac{2ma}{g + a} \] ### Conclusion The mass that should be removed from the balloon so that it starts moving upwards with an acceleration `a` is: \[ m' = \frac{2ma}{g + a} \] ### Final Answer The correct option is **Option 4: \( m' = \frac{2ma}{g + a} \)**. ---
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