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A person can hear frequencies only upto ...

A person can hear frequencies only upto 10kHz. A steel piano pipe wire 50cm long of mass 5g is streched with a tension of 400N. The number of the hightest overtone of the sound produced by this plano wire that the person can hear is

A

48

B

50

C

49

D

51

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the principles of wave motion and the properties of vibrating strings. ### Step 1: Understand the given data - Maximum frequency a person can hear, \( f_{max} = 10 \, \text{kHz} = 10 \times 10^3 \, \text{Hz} \) - Length of the wire, \( L = 50 \, \text{cm} = 0.5 \, \text{m} \) - Mass of the wire, \( m = 5 \, \text{g} = 5 \times 10^{-3} \, \text{kg} \) - Tension in the wire, \( T = 400 \, \text{N} \) ### Step 2: Calculate the linear mass density (\( \mu \)) The linear mass density \( \mu \) is given by: \[ \mu = \frac{m}{L} \] Substituting the values: \[ \mu = \frac{5 \times 10^{-3} \, \text{kg}}{0.5 \, \text{m}} = 0.01 \, \text{kg/m} \] ### Step 3: Calculate the wave speed (\( V \)) The wave speed \( V \) in the wire can be calculated using the formula: \[ V = \sqrt{\frac{T}{\mu}} \] Substituting the values: \[ V = \sqrt{\frac{400 \, \text{N}}{0.01 \, \text{kg/m}}} = \sqrt{40000} = 200 \, \text{m/s} \] ### Step 4: Calculate the fundamental frequency (\( f_1 \)) The fundamental frequency \( f_1 \) is given by the formula: \[ f_1 = \frac{V}{2L} \] Substituting the values: \[ f_1 = \frac{200 \, \text{m/s}}{2 \times 0.5 \, \text{m}} = \frac{200}{1} = 200 \, \text{Hz} \] ### Step 5: Calculate the overtone frequencies The frequency of the \( n \)-th overtone is given by: \[ f_n = n \cdot f_1 \] Thus, the maximum frequency that can be heard is: \[ f_n \leq f_{max} \] Substituting the values: \[ n \cdot 200 \, \text{Hz} \leq 10 \times 10^3 \, \text{Hz} \] \[ n \leq \frac{10 \times 10^3}{200} = 50 \] ### Step 6: Determine the highest overtone The highest overtone is given by: \[ \text{Highest overtone} = n - 1 \] Substituting the value of \( n \): \[ \text{Highest overtone} = 50 - 1 = 49 \] ### Final Answer The number of the highest overtone of the sound produced by this piano wire that the person can hear is **49**. ---
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