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A Uniform rope having mass m hags vertic...

A Uniform rope having mass m hags vertically from a rigid support. A transverse wave pulse is produced at the lower end. The speed v of wave pulse varies with height h from the lower end as

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To solve the problem, we need to determine how the speed \( v \) of a transverse wave pulse in a hanging rope varies with the height \( h \) from the lower end of the rope. Here’s a step-by-step solution: ### Step 1: Understand the relationship between wave speed, tension, and linear mass density The speed \( v \) of a wave in a rope is given by the formula: \[ v = \sqrt{\frac{T}{\mu}} \] where \( T \) is the tension in the rope and \( \mu \) is the linear mass density of the rope. ### Step 2: Determine the tension in the rope at a height \( h \) Consider a small segment of the rope of length \( x \) from the bottom. The mass of this segment is: \[ m_x = \mu x \] The tension \( T \) at height \( h \) is due to the weight of the rope below that point. Therefore, the tension can be expressed as: \[ T = m_x g = \mu x g \] where \( g \) is the acceleration due to gravity. ### Step 3: Substitute the tension into the wave speed formula Substituting the expression for tension into the wave speed formula, we get: \[ v = \sqrt{\frac{\mu x g}{\mu}} = \sqrt{x g} \] ### Step 4: Relate height \( h \) to the length \( x \) Since the rope is hanging vertically, the height \( h \) from the bottom of the rope is related to the length \( x \) of the rope below the point of interest. Thus, we can express \( x \) in terms of \( h \): \[ x = L - h \] where \( L \) is the total length of the rope. ### Step 5: Substitute \( x \) into the wave speed equation Now substituting \( x = L - h \) into the wave speed equation gives: \[ v = \sqrt{(L - h) g} \] ### Step 6: Analyze the relationship between \( v \) and \( h \) From the equation \( v = \sqrt{(L - h) g} \), we can see that as \( h \) increases (moving up the rope), \( v \) decreases. The relationship is a square root function, which indicates that the speed \( v \) varies with height \( h \) in a parabolic manner. ### Conclusion Thus, the speed \( v \) of the wave pulse varies with height \( h \) from the lower end of the rope as: \[ v \propto \sqrt{(L - h)} \] This indicates that the speed decreases as we move up the rope.
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