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A closed organ pipe and an open organ pi...

A closed organ pipe and an open organ pipe of same length produce 2 beats when they are set into vibrations simultaneously in their fundamental mode. The length of open organ pipe is now halved and of closed organ pipe is doubled, the number of beats produced wil be
(A)8 (B)7 (C)4 (D)2

A

8

B

7

C

4

D

2

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to follow these steps: ### Step 1: Understand the fundamental frequencies of the pipes For a closed organ pipe, the fundamental frequency \( f_c \) is given by: \[ f_c = \frac{V}{4L} \] For an open organ pipe, the fundamental frequency \( f_o \) is given by: \[ f_o = \frac{V}{2L} \] ### Step 2: Set up the initial conditions Initially, both pipes have the same length \( L \). According to the problem, they produce 2 beats when vibrating simultaneously: \[ |f_o - f_c| = 2 \] Substituting the expressions for \( f_o \) and \( f_c \): \[ \left| \frac{V}{2L} - \frac{V}{4L} \right| = 2 \] ### Step 3: Simplify the equation Simplifying the left side: \[ \left| \frac{2V}{4L} - \frac{V}{4L} \right| = \left| \frac{V}{4L} \right| = 2 \] This gives us: \[ \frac{V}{4L} = 2 \implies V = 8L \] ### Step 4: Analyze the new lengths of the pipes Now, the length of the open organ pipe is halved, so its new length \( L' = \frac{L}{2} \). The closed organ pipe's length is doubled, so its new length \( L'' = 2L \). ### Step 5: Calculate the new fundamental frequencies For the new open organ pipe: \[ f_o' = \frac{V}{2L'} = \frac{V}{2 \cdot \frac{L}{2}} = \frac{V}{L} \] For the new closed organ pipe: \[ f_c' = \frac{V}{4L''} = \frac{V}{4 \cdot 2L} = \frac{V}{8L} \] ### Step 6: Calculate the new number of beats Now, we find the number of beats produced: \[ |f_o' - f_c'| = \left| \frac{V}{L} - \frac{V}{8L} \right| \] Simplifying this: \[ = \left| \frac{8V}{8L} - \frac{V}{8L} \right| = \left| \frac{7V}{8L} \right| \] ### Step 7: Substitute the value of \( V \) From our earlier calculation, we found \( V = 8L \): \[ |f_o' - f_c'| = \left| \frac{7 \cdot 8L}{8L} \right| = 7 \] ### Final Answer Thus, the number of beats produced when the lengths are changed is: \[ \boxed{7} \]
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