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when a source of sound of frequency f cr...

when a source of sound of frequency f crosses stationary observer with a speed ` v_(s) (lt lt ` speed of sound v) , the apparent change in frequency ` Δf` is given by

A

`(2fv_(s))/v`

B

`2fs v_(s)`

C

`(2fv_(s))/v_(s)`

D

`(fv_(s))/v`

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The correct Answer is:
To solve the problem of finding the apparent change in frequency \( \Delta f \) when a source of sound of frequency \( f \) crosses a stationary observer with speed \( v_s \) (where \( v_s \) is much less than the speed of sound \( v \)), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Frequencies**: - The frequency of the source is \( f \). - When the source approaches the observer, the apparent frequency \( f_1 \) is given by the formula: \[ f_1 = f \frac{v}{v - v_s} \] - When the source moves away from the observer, the apparent frequency \( f_2 \) is given by: \[ f_2 = f \frac{v}{v + v_s} \] 2. **Calculate the Change in Frequency**: - The change in frequency \( \Delta f \) is defined as: \[ \Delta f = f_1 - f_2 \] - Substituting the expressions for \( f_1 \) and \( f_2 \): \[ \Delta f = f \frac{v}{v - v_s} - f \frac{v}{v + v_s} \] 3. **Factor Out \( f \)**: - We can factor \( f \) out of the equation: \[ \Delta f = f \left( \frac{v}{v - v_s} - \frac{v}{v + v_s} \right) \] 4. **Combine the Fractions**: - To combine the fractions, we need a common denominator: \[ \Delta f = f \left( \frac{v(v + v_s) - v(v - v_s)}{(v - v_s)(v + v_s)} \right) \] - Simplifying the numerator: \[ v(v + v_s) - v(v - v_s) = v^2 + vv_s - v^2 + vv_s = 2vv_s \] - Thus, we have: \[ \Delta f = f \left( \frac{2vv_s}{(v - v_s)(v + v_s)} \right) \] 5. **Approximate for Small \( v_s \)**: - Since \( v_s \) is much smaller than \( v \) (i.e., \( v_s \ll v \)), we can approximate: \[ (v - v_s)(v + v_s) \approx v^2 \] - Therefore, the equation simplifies to: \[ \Delta f \approx f \left( \frac{2vv_s}{v^2} \right) = \frac{2f v_s}{v} \] 6. **Final Result**: - The apparent change in frequency \( \Delta f \) is given by: \[ \Delta f = \frac{2f v_s}{v} \] ### Summary: The apparent change in frequency when a source of sound crosses a stationary observer is given by: \[ \Delta f = \frac{2f v_s}{v} \]
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