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A closed organ pipe of length 1.2 m vi...

A closed organ pipe of length 1.2 m vibrates in its first overtone mode . The pressue variation is maximum at

A

0.8m from the open end

B

0.4m from the open end

C

closed end

D

1.0m from the open end

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The correct Answer is:
To solve the problem of where the pressure variation is maximum in a closed organ pipe vibrating in its first overtone mode, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Closed Organ Pipe**: - A closed organ pipe has one end closed and one end open. In such pipes, the closed end is a node (minimum pressure variation) and the open end is an antinode (maximum pressure variation). 2. **Identify the Mode of Vibration**: - The first overtone mode (also known as the second harmonic) in a closed organ pipe consists of one node at the closed end and one antinode at the open end, with an additional node and antinode in between. 3. **Determine the Length of the Pipe**: - Given that the length \( L \) of the closed organ pipe is 1.2 m. 4. **Relate the Length to Wavelength**: - For a closed organ pipe, the relationship between the length of the pipe and the wavelength \( \lambda \) in the first overtone mode is given by: \[ L = \frac{3\lambda}{4} \] - This is because in the first overtone mode, there are three-quarters of a wavelength fitting into the length of the pipe. 5. **Calculate the Wavelength**: - Rearranging the equation gives: \[ \lambda = \frac{4L}{3} \] - Substituting \( L = 1.2 \) m: \[ \lambda = \frac{4 \times 1.2}{3} = \frac{4.8}{3} = 1.6 \text{ m} \] 6. **Determine the Position of Maximum Pressure Variation**: - In the first overtone mode, the pressure variation is maximum at the antinode, which is located at a distance of \( \frac{1}{4} \lambda \) from the closed end. - Calculate \( \frac{1}{4} \lambda \): \[ \frac{1}{4} \lambda = \frac{1.6}{4} = 0.4 \text{ m} \] 7. **Final Answer**: - Therefore, the pressure variation is maximum at a distance of 0.4 m from the closed end of the pipe. ### Summary: The pressure variation is maximum at 0.4 m from the closed end of the organ pipe. ---
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