Home
Class 11
PHYSICS
From a single source, two wave trains ar...

From a single source, two wave trains are sent in two different string. The two wave equations are ((area of cross-section and tension of both string are same `y_(1) ` = A sin (`w_(1)t-k_(1)x)and y_(2) = 2A sin (w_(1)t -k_(2)z)`Suppose u = energy density , P = power trasmitted and I = intensity of the wave, then match the following.

Text Solution

Verified by Experts

The correct Answer is:
(a)Q, (b)P, (c )P
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    DC PANDEY ENGLISH|Exercise Integer Type Question|11 Videos

  • WAVE MOTION

    DC PANDEY ENGLISH|Exercise Comprehion Type Questions|20 Videos

  • VECTORS

    DC PANDEY ENGLISH|Exercise Medical enrances gallery|9 Videos

  • WORK, ENERGY & POWER

    DC PANDEY ENGLISH|Exercise Level 2 Comprehension Based|2 Videos

Similar Questions

Explore conceptually related problems

Two waves y_1 = A sin (omegat - kx) and y_2 = A sin (omegat + kx) superimpose to produce a stationary wave, then

When two progressive waves y_(1) = 4 sin (2x - 6t) and y_(2) = 3 sin (2x - 6t - (pi)/(2)) are superimposed, the amplitude of the resultant wave is

When two progressive waves y_(1) = 4 sin (2x - 6t) and y_(2) = 3 sin (2x - 6t - (pi)/(2)) are superimposed, the amplitude of the resultant wave is

Equations of two progressive wave are given by y_(1) = asin (omega t + phi_(1)) and y_(2) = a sin (omegat + phi_(2)) . IF amplitude and time period of resultant wave is same as that of both the waves, then (phi_(1)-phi_(2)) is

Two waves, whose equations are y_(1)=4sin(20t-(x)/(3))m and y_(2)=3sin(20t-(x)/(3)) m, are superposed in a medium. Now,

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .

Two waves are passing through a region in the same direction at the same time . If the equation of these waves are y_(1) = a sin ( 2pi)/(lambda)( v t - x) and y_(2) = b sin ( 2pi)/( lambda) [( vt - x) + x_(0) ] then the amplitude of the resulting wave for x_(0) = (lambda//2) is

Two waves are represented by the following equations y_(1) = 5 sin 2pi (10t -0.1 x) y_(2) = 10 sin 2pi (20t - 0.2 x) Ratio of intensites I_(2)//I_(1) will be

Both the strings, shown in figure, are made of same material and have same cross-section. The pulleys are light. The wave speed of transverse wave in the string AB is v_(1) and in CD it is v_(2) , the v_(1)//v_(2) is

The equation of a wave travelling on a string is given by Y(mn) = 8 sin[ (5m^(-1)x-(4s^(-1)t ]. Then