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A transistor has three impurity regions ...

A transistor has three impurity regions , emitter , base and collector. Arrange them in order of increasing doping levels.

A

emitter, base and collector

B

collector, base and emitter

C

base, emitter and collector

D

base, collector and emitter

Text Solution

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The correct Answer is:
To solve the question of arranging the impurity regions of a transistor (emitter, base, and collector) in order of increasing doping levels, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Function of Each Region**: - The **emitter** is responsible for injecting charge carriers (electrons or holes) into the base. It needs to be highly doped to ensure a large number of charge carriers are available for injection. - The **base** is the region where the charge carriers recombine. It is intentionally kept lightly doped to allow for efficient control of the charge carriers flowing from the emitter to the collector. - The **collector** collects the charge carriers that have traversed the base. It is moderately doped, more than the base but less than the emitter. 2. **Identify Doping Levels**: - **Emitter**: Highly doped (highest concentration of impurities). - **Collector**: Moderately doped (intermediate concentration of impurities). - **Base**: Lightly doped (lowest concentration of impurities). 3. **Arrange in Order of Increasing Doping Levels**: - Based on the doping levels identified, we can arrange them as follows: - Base (least doped) - Collector (moderately doped) - Emitter (most doped) 4. **Final Arrangement**: - Therefore, the order of increasing doping levels is: **Base < Collector < Emitter**. ### Conclusion: The correct arrangement of the transistor regions in order of increasing doping levels is: **Base, Collector, Emitter**.
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