What is `beta` value for transistor whose `alpha=0.98`?

Options

A. 29
B. 38
C. 49
D. 56

Answer

To find the value of `beta` for a transistor given that `alpha = 0.98`, we can use the relationship between `alpha` and `beta`. The formula is:

\[ \beta = \frac{\alpha}{1 - \alpha} \]

### Step-by-Step Solution:

1. **Write down the formula**: Start with the relationship between `alpha` and `beta`.
\[ \beta = \frac{\alpha}{1 - \alpha} \]

2. **Substitute the value of `alpha`**: We know that `alpha = 0.98`, so we substitute this value into the formula.
\[ \beta = \frac{0.98}{1 - 0.98} \]

3. **Calculate `1 - alpha`**: Now, calculate `1 - 0.98`.
\[ 1 - 0.98 = 0.02 \]

4. **Substitute back into the equation**: Replace `1 - alpha` in the formula with `0.02`.
\[ \beta = \frac{0.98}{0.02} \]

5. **Perform the division**: Now, divide `0.98` by `0.02`.
\[ \beta = 49 \]

6. **Conclusion**: The value of `beta` for the transistor is `49`.

### Final Answer:
\[ \beta = 49 \]