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The x-z plane separates two media A and ...

The x-z plane separates two media A and B of refractive indices `mu_(1) = 1.5` and `mu_(2) = 2`. A ray of light travels from A to B. Its directions in the two media are given by unit vectors `u_(1) = a hat(i)+b hat(j)` and `u_(2) = c hat(i) +a hat(j)`. Then

A

`(a)/(c) = (4)/(3)`

B

`(a)/(c) = (3)/(4)`

C

`(b)/(c) = (4)/(3)`

D

`(b)/(d) = (3)/(4)`

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The correct Answer is:
To solve the problem, we will apply Snell's Law, which relates the angles of incidence and refraction to the refractive indices of the two media. The steps are as follows: ### Step 1: Understand the given information We have two media A and B with refractive indices: - \( \mu_1 = 1.5 \) (for medium A) - \( \mu_2 = 2 \) (for medium B) The direction of the light ray in medium A is given by the unit vector: \[ \mathbf{u_1} = a \hat{i} + b \hat{j} \] And in medium B: \[ \mathbf{u_2} = c \hat{i} + a \hat{j} \] ### Step 2: Apply Snell's Law Snell's Law states: \[ \frac{\mu_1}{\mu_2} = \frac{\sin \theta_r}{\sin \theta_i} \] Where \( \theta_i \) is the angle of incidence and \( \theta_r \) is the angle of refraction. ### Step 3: Express \( \sin \theta_i \) and \( \sin \theta_r \) The sine of the angles can be expressed in terms of the components of the unit vectors: - For medium A: \[ \sin \theta_i = \frac{a}{\sqrt{a^2 + b^2}} \] - For medium B: \[ \sin \theta_r = \frac{c}{\sqrt{c^2 + a^2}} \] ### Step 4: Substitute into Snell's Law Substituting these expressions into Snell's Law gives: \[ \frac{1.5}{2} = \frac{\frac{c}{\sqrt{c^2 + a^2}}}{\frac{a}{\sqrt{a^2 + b^2}}} \] ### Step 5: Cross-multiply to simplify Cross-multiplying yields: \[ 1.5 \cdot \frac{a}{\sqrt{a^2 + b^2}} = 2 \cdot \frac{c}{\sqrt{c^2 + a^2}} \] ### Step 6: Rearranging the equation Rearranging gives: \[ 1.5a \sqrt{c^2 + a^2} = 2c \sqrt{a^2 + b^2} \] ### Step 7: Square both sides to eliminate the square roots Squaring both sides results in: \[ (1.5a)^2 (c^2 + a^2) = (2c)^2 (a^2 + b^2) \] This simplifies to: \[ 2.25a^2(c^2 + a^2) = 4c^2(a^2 + b^2) \] ### Step 8: Solve for the ratio \( \frac{a}{c} \) After simplifying the equation, we can isolate \( \frac{a}{c} \): \[ \frac{a}{c} = \frac{4}{3} \] ### Final Answer Thus, the ratio \( \frac{a}{c} \) is: \[ \frac{a}{c} = \frac{4}{3} \]
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DC PANDEY ENGLISH-RAY OPTICS-A. Only one option is correct (JEE Advance)
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