The position of a particle is given by
`x=2(t-t^(2))`
where `t` is expressed in seconds and `x` is in metre.
When does the object return to its initial velocity?

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. When is the object at rest?

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The particle

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The acceleration of the particle is

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The maximum value of position co-ordinate of particle on positive x -axis is

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The total distance travelled by the paticle between t=0 to t=1s is

The position of a particle is given by vec r =(8 t hati +3t^(2) +5 hatk) m where t is measured in second and vec r in meter. Calculate, the magnitude of velocity at t = 5 s,

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.

The velocity of a particle is given by v=(4t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=1 second.

The position of a particle is given by vec r =(8 t hati +3t^(2) hatj +5 hatk) m where t is measured in second and vec r in meter. Calculate, direction of the velocity at t = 1 s

The position of a particle along the x-axis is given by the equation, x=t^(3)-6t^(2)+9t , where t is measured in seconds and x in meters. (a) Find the velocity at time t (b) What is the velocity at t = 2 s, at = t = 4 s? (c) What is the time instant, when particle is at rest?