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Five identical cells are connected in pa...

Five identical cells are connected in parallel. Now, polarity of one of the cells is reversed. Percentage change in equivalent emf will be

A

-0.1

B

-0.2

C

-0.4

D

-0.6

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To solve the problem of finding the percentage change in equivalent EMF when one of the five identical cells connected in parallel has its polarity reversed, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Initial Configuration:** - We have five identical cells connected in parallel. - Let the EMF of each cell be \( E \) and the internal resistance of each cell be \( r \). 2. **Calculating the Equivalent EMF for All Cells in Parallel:** - When all five cells are connected in parallel, the equivalent EMF (\( E_{\text{initial}} \)) is given by: \[ E_{\text{initial}} = E \] - This is because in parallel, the EMF remains the same as that of one cell. 3. **Reversing the Polarity of One Cell:** - When one cell's polarity is reversed, we effectively have four cells contributing positively and one cell contributing negatively. - The equivalent EMF (\( E_{\text{final}} \)) can be calculated as: \[ E_{\text{final}} = E + E + E + E - E = 4E - E = 3E \] - Since they are in parallel, we can express the equivalent EMF as: \[ E_{\text{final}} = \frac{3E}{5} \] 4. **Calculating the Percentage Change in EMF:** - The percentage change in equivalent EMF can be calculated using the formula: \[ \text{Percentage Change} = \frac{E_{\text{final}} - E_{\text{initial}}}{E_{\text{initial}}} \times 100 \] - Substituting the values: \[ \text{Percentage Change} = \frac{\frac{3E}{5} - E}{E} \times 100 \] - Simplifying the equation: \[ = \frac{\frac{3E}{5} - \frac{5E}{5}}{E} \times 100 = \frac{-2E}{5E} \times 100 = -40\% \] 5. **Conclusion:** - The percentage change in equivalent EMF when one of the cells has its polarity reversed is \(-40\%\). The negative sign indicates a decrease in EMF.
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