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One mole of a diatomic gas undergoes a p...

One mole of a diatomic gas undergoes a process `P = P_(0)//[1 + (V//V_(0)^(3))]` where `P_(0)` and `V_(0)` are constant. The translational kinetic energy of the gas when `V = V_(0)` is given by

A

`(5p_(0)V_(0))/(4)`

B

`(3p_(0)V_(0))/(4)`

C

`(3p_(0)V_(0))/(2)`

D

`(5p_(0)V_(0))/(2)`

Text Solution

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The correct Answer is:
B
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