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The magnitude of energy, the magnitude o...

The magnitude of energy, the magnitude of linear momentum and orbital radius of an electron in a hydrogen atom corresponding to the quantum number n are `E, P` and r respectively. Then according to Bohr's theory of hydrogen atom:

A

Epr is proportinal to `(1)/(n)`

B

P/E is proportional to n

C

Er is constant for all orbits

D

Pr is proportional to n

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The correct Answer is:
To solve the problem, we need to analyze the relationships between the energy (E), linear momentum (P), and orbital radius (r) of an electron in a hydrogen atom according to Bohr's theory. ### Step-by-Step Solution: 1. **Energy of the Electron (E)**: According to Bohr's theory, the energy of an electron in a hydrogen atom is given by: \[ E_n = -\frac{13.6 \text{ eV}}{n^2} \] This shows that the energy is inversely proportional to the square of the principal quantum number \(n\): \[ E \propto \frac{1}{n^2} \] 2. **Linear Momentum of the Electron (P)**: The linear momentum of the electron can be expressed as: \[ P_n = m v_n \] where \(v_n\) is the velocity of the electron in the nth orbit. From Bohr's model, we find that: \[ v_n \propto \frac{1}{n} \] Therefore, the momentum is also inversely proportional to \(n\): \[ P \propto \frac{1}{n} \] 3. **Orbital Radius of the Electron (r)**: The radius of the electron's orbit is given by: \[ r_n = n^2 a_0 \] where \(a_0\) is the Bohr radius. This shows that the radius is directly proportional to the square of the quantum number \(n\): \[ r \propto n^2 \] 4. **Analyzing Relationships**: Now we can summarize the relationships: - \(E \propto \frac{1}{n^2}\) - \(P \propto \frac{1}{n}\) - \(r \propto n^2\) 5. **Finding the Relationships**: We can analyze the ratios: - For \(E \cdot P \cdot r\): \[ E \cdot P \cdot r \propto \left(\frac{1}{n^2}\right) \cdot \left(\frac{1}{n}\right) \cdot (n^2) = \frac{1}{n^2} \cdot \frac{1}{n} \cdot n^2 = \frac{1}{n} \] - For \(\frac{E}{P}\): \[ \frac{E}{P} \propto \frac{\frac{1}{n^2}}{\frac{1}{n}} = \frac{1}{n} \] - For \(E \cdot r\): \[ E \cdot r \propto \left(\frac{1}{n^2}\right) \cdot (n^2) = 1 \] 6. **Conclusion**: From the analysis, we find that: - \(E \cdot r\) is constant. - \(\frac{E}{P}\) is not constant. - \(E \cdot P \cdot r\) is not constant. Thus, the correct relationship according to Bohr's theory is that \(E \cdot r\) is constant for all orbits. ### Final Answer: The correct option is \(C\): \(E \cdot r\) is constant.
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