Home
Class 12
PHYSICS
Single electron is orbiting in n^(th)orb...

Single electron is orbiting in `n^(th)`orbit of hydrogen atom. The magnetic field produced by the electron at the nucleus will be proportional to `n^(-k)` . Find the value of k.

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( k \) in the expression for the magnetic field produced by an electron in the \( n^{th} \) orbit of a hydrogen atom, we can follow these steps: ### Step 1: Understand the Magnetic Field at the Nucleus The magnetic field \( B \) at the center of a circular current loop is given by the formula: \[ B = \frac{\mu_0 I}{2R} \] where \( \mu_0 \) is the permeability of free space, \( I \) is the current, and \( R \) is the radius of the circular path. ### Step 2: Determine the Current Due to the Electron The current \( I \) due to an electron moving in a circular orbit can be expressed as: \[ I = \frac{e}{T} \] where \( e \) is the charge of the electron and \( T \) is the time period of the electron's orbit. The time period \( T \) for an electron in the \( n^{th} \) orbit is given by: \[ T = \frac{2\pi r_n}{v_n} \] where \( r_n \) is the radius of the \( n^{th} \) orbit and \( v_n \) is the velocity of the electron in that orbit. ### Step 3: Substitute the Time Period into the Current Expression Substituting \( T \) into the current expression gives: \[ I = \frac{e v_n}{2\pi r_n} \] ### Step 4: Substitute Current into the Magnetic Field Formula Now, substituting the expression for current \( I \) into the magnetic field formula: \[ B = \frac{\mu_0}{2R} \cdot \frac{e v_n}{2\pi r_n} \] ### Step 5: Analyze the Relationships of Velocity and Radius From Bohr's model of the hydrogen atom: - The radius \( r_n \) of the \( n^{th} \) orbit is proportional to \( n^2 \): \[ r_n \propto n^2 \] - The velocity \( v_n \) of the electron in the \( n^{th} \) orbit is inversely proportional to \( n \): \[ v_n \propto \frac{1}{n} \] ### Step 6: Substitute the Proportional Relationships Substituting these relationships into the expression for \( B \): \[ B \propto \frac{v_n}{r_n^2} \propto \frac{1/n}{(n^2)^2} = \frac{1/n}{n^4} = \frac{1}{n^5} \] ### Step 7: Determine the Value of \( k \) From the expression \( B \propto n^{-5} \), we can see that: \[ k = 5 \] ### Final Answer Thus, the value of \( k \) is: \[ \boxed{5} \]
Promotional Banner

Topper's Solved these Questions

  • MODERN PHYSICS

    DC PANDEY ENGLISH|Exercise Metch the column|6 Videos
  • MAGNETISM AND MATTER

    DC PANDEY ENGLISH|Exercise Medical gallery|1 Videos
  • MODERN PHYSICS - 1

    DC PANDEY ENGLISH|Exercise Level 2 Subjective|23 Videos

Similar Questions

Explore conceptually related problems

Magnetic moment of an electron in nth orbit of hydrogen atom is

Magnetic moment of an electron in nth orbit of hydrogen atom is

An electron orbiting around a nucleus has angular momentum L. The magnetic field produced by the electron at the centre of the orbit can be expressed as :

Angular velocity of an electron in nth Bohr orbit is proportional to (1)/(n^((p)/(2))) .Find the value of p

An electrons is revolving in n=3 orbit. What will be the magnetic field at the centre of hydrogen atom.

According to Bohr model, magnetic field at the centre (at the nucleus) of a hydrogen atom due to the motion of the electron in nth orbit is proportional to 1//n^(x) , find the value of x

In a hydrogen atom , the electron atom makes a transition from n = 2 to n = 1 . The magnetic field produced by the circulating electron at the nucleus

An electron moving in a circular orbit of radius makes n rotations per second. The magnetic field produced at the centre has magnitude :

In an atom the ratio of radius of orbit of electron to the radius of nucleus is

The orbital frequency of an electron in the hydrogen atom is proportional to

DC PANDEY ENGLISH-MODERN PHYSICS-Integer Type Questions
  1. The ratio between acceleration of the electron in singlely ionized hel...

    Text Solution

    |

  2. If the radius of firs Bohr's orbit is x, then de-Broglie wavelenght of...

    Text Solution

    |

  3. A H-atom moving with speed v makes a head on collisioon with a H-atom ...

    Text Solution

    |

  4. The magnetic fieold at the centre of a hydrogen atom due to the motion...

    Text Solution

    |

  5. when the voltage applied to an X-ray tube increases from V(1) = 10 kV ...

    Text Solution

    |

  6. Light of wavelength 330nm falling on a piece of metal ejects electrons...

    Text Solution

    |

  7. Light of wavelength 0.6mum from a sodium lamp falls on a photocell and...

    Text Solution

    |

  8. An alpha-particle accelerated through V volt is fired towards a nucleu...

    Text Solution

    |

  9. The kinetic energies of the photoelectrons ejected from a metal surfac...

    Text Solution

    |

  10. In a hydrogen atom following the Bohr's psotulates the product of line...

    Text Solution

    |

  11. A target element A is bombarded with electrons and the wavelengths of ...

    Text Solution

    |

  12. A moving hydrogen atom makes a head on collision with a stationary hy...

    Text Solution

    |

  13. A radioactive sample contains two different types of radioactive nucle...

    Text Solution

    |

  14. A overset(lambda)rarr B overset(2 lambda)rarr C T=0 ,N(0) , 0 , T...

    Text Solution

    |

  15. In a photeclectric experiment , when electromegnetic wave given by E=E...

    Text Solution

    |

  16. Nuclei X and Y convert into a stable nucleus Z. At t=0 , the number o...

    Text Solution

    |

  17. Single electron is orbiting in n^(th)orbit of hydrogen atom. The magne...

    Text Solution

    |