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The Coefficient of cubical expansion of ...

The Coefficient of cubical expansion of mercury is `0.0018//^(@)C` and that of brass `0.000006//^(@)C`, find the true barmetric height at `0^(@)C`.The scale is supposed to be coreect at `15^(@)C`

A

74.122 cm

B

79.125 cm

C

42.161cm

D

142.39 cm

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The correct Answer is:
To find the true barometric height at \(0^\circ C\) given the coefficients of cubical expansion for mercury and brass, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values**: - Coefficient of cubical expansion of mercury (\(\gamma\)): \(0.0018 \, /^\circ C\) - Coefficient of cubical expansion of brass (\(\alpha\)): \(0.000006 \, /^\circ C\) - Initial barometric height at \(15^\circ C\) (\(h_0\)): \(760 \, mm\) (which is equivalent to \(76 \, cm\)) - Change in temperature (\(\Delta t\)): \(0^\circ C - 15^\circ C = -15^\circ C\) 2. **Use the Formula for True Barometric Height**: The formula for the true barometric height (\(h\)) at a different temperature is given by: \[ h = h_0 \left(1 - \left(\gamma - \alpha\right) \Delta t\right) \] 3. **Substitute the Values into the Formula**: - Substitute \(h_0 = 76 \, cm\), \(\gamma = 0.0018 \, /^\circ C\), \(\alpha = 0.000006 \, /^\circ C\), and \(\Delta t = -15^\circ C\) into the formula: \[ h = 76 \left(1 - \left(0.0018 - 0.000006\right)(-15)\right) \] 4. **Calculate the Difference in Coefficients**: - Calculate \(\gamma - \alpha\): \[ \gamma - \alpha = 0.0018 - 0.000006 = 0.001794 \] 5. **Calculate the Product with \(\Delta t\)**: - Now calculate \((\gamma - \alpha) \Delta t\): \[ (\gamma - \alpha)(-15) = 0.001794 \times (-15) = -0.02691 \] 6. **Substitute Back into the Height Equation**: \[ h = 76 \left(1 + 0.02691\right) = 76 \times 1.02691 \] 7. **Final Calculation**: - Now calculate \(h\): \[ h \approx 76 \times 1.02691 \approx 77.04 \, cm \] ### Final Answer: The true barometric height at \(0^\circ C\) is approximately \(77.04 \, cm\).
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