A pipe of length 85cm is closed from one...

A pipe of length `85cm` is closed from one end. Find the number of possible natural oscillations of air column in the pipe whose frequencies lie below `1250 Hz`. The velocity of sound in air is `340m//s`.

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The number of possible natural oscillations of air column in a pipe closed at one end of length 85 cm whose frequencies lie below 1250 Hz are (velocity of sound =340ms^(-1) ).

Find the number of possible natural oscillations of air column in a pipe whose frequencies lie below f_(0) = 1250 Hz . The length of the pipe is l = 85 cm . The velocity of sound is v = 340 m//s . Consider two cases the pipe is closed from one end .

Find the number of possible natural oscillations of air column in a pipe frequencies of which lie below v_(0) = 1250 Hz . The length of the pipe is l = 85 cm . The velocity of sound is v = 340 m//s . Consider two cases i. the pipe is closed from the end , ii. the pipe is open from both ends.

How many frequencies below 1 kH_(Z) of natural oscillations of air column will be produced if a pipe of length 1 m is closed at one end? [ velocity of sound in air is 340 m//s ]

A pipe 1 m length is closed at one end. Taking the speed of sound in air as 320ms ^(-1) .the air column in the pipe cannot resonate for the frequency (in Hz )

Calculate the frequency of fifth harmonic of a closed organ pipe of length 50cm, if the velocity of sound in air is 330 m/s.

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A narrow pipe of length 2m is closed at one end. The velocity of sound in air is 320 m/s. Neglecting end corrections , the air column in the pipe will resonate for sound of frequencies :

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