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Assertion The maximum height of projecti...

Assertion The maximum height of projectile is always 25% of the maximum range.
Reasons For maximum range, projectile should be projected at `90^(@)`

A

Both Assertion and Reason are correct, Reason is the coreect expianation of Assertion

B

Bioth Assertion and Reason are Correct but Reason is not the correct expalnation of Assertion

C

Assetion is correct and Reason is incorrect

D

Assertion is incorrect and Reason is correct

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the assertion and the reason given in the question. ### Step 1: Understanding the Assertion The assertion states that the maximum height of a projectile is always 25% of the maximum range. ### Step 2: Formulas for Maximum Height and Range 1. **Maximum Range (R)** of a projectile is given by the formula: \[ R = \frac{u^2 \sin(2\theta)}{g} \] For maximum range, the angle \(\theta\) should be \(45^\circ\) because \(\sin(90^\circ) = 1\). Thus, the maximum range becomes: \[ R_{\text{max}} = \frac{u^2}{g} \] 2. **Maximum Height (H)** of a projectile is given by the formula: \[ H = \frac{u^2 \sin^2(\theta)}{2g} \] At \(\theta = 45^\circ\), we have: \[ H = \frac{u^2 \sin^2(45^\circ)}{2g} = \frac{u^2 \left(\frac{1}{\sqrt{2}}\right)^2}{2g} = \frac{u^2 \cdot \frac{1}{2}}{2g} = \frac{u^2}{4g} \] ### Step 3: Relating Maximum Height to Maximum Range From the above calculations, we can relate the maximum height \(H\) to the maximum range \(R_{\text{max}}\): \[ H = \frac{u^2}{4g} \quad \text{and} \quad R_{\text{max}} = \frac{u^2}{g} \] Now, if we express \(H\) in terms of \(R_{\text{max}}\): \[ H = \frac{R_{\text{max}}}{4} \] This shows that the maximum height is indeed 25% of the maximum range. ### Step 4: Analyzing the Reason The reason states that for maximum range, the projectile should be projected at \(90^\circ\). This is incorrect because the angle for maximum range is actually \(45^\circ\). ### Conclusion - The assertion is **correct**: The maximum height of a projectile is always 25% of the maximum range. - The reason is **incorrect**: The angle for maximum range is \(45^\circ\), not \(90^\circ\). Thus, the correct answer is that the assertion is true, but the reason is false. ### Final Answer Assertion is correct, but the reason is incorrect. ---
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