An object has a velocity, `v = (2hati + 4hatj) ms^(-1)` at time `t = 0s`. It undergoes a constant acceleration `a = (hati - 3hatj)ms^(-2)` for 4s. Then
(i) Find the coordinates of the object if it is at origin at `t = 0`
(ii) Find the magnitude of its velocity at the end of 4s.

Explanation

To solve the problem, we will break it down into two parts as stated in the question.

### Part (i): Find the coordinates of the object after 4 seconds.

1. **Initial Position**: The object is at the origin at `t = 0`. Therefore, the initial position vector \( \mathbf{r_1} \) is:
\[ \mathbf{r_1} = 0 \hat{i} + 0 \hat{j} = \mathbf{0} \]
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