A cricket ball is thrown at a speed of ` 28 ms^(-1)` in a direction `30 ^(@)` above the horizontal. Calculate (a)the maximum height (b) the time taken by ball to return to the same level, and (c )the distance from the thrower to the point where the ball returns to the same level.

Explanation

Given, speed `u = 28 ms^(-1)` and `theta = 30^(@)`
`:.` The time taken by the ball to return the same level is
`T = (2u sin theta)/(g) = (2xx 28 xx sin 30^(@))/(9.8) = (28)/(9.8) = 2.9 s`.