Assume that a ball is kicked at an angle of `60^(@)` with the horizontal, so if the horizontal component of its velocity is `19.6 ms^(-1)`, determine its maximum height.

Explanation

To determine the maximum height attained by a ball kicked at an angle of \(60^\circ\) with a horizontal component of velocity \(19.6 \, \text{m/s}\), we can follow these steps:

### Step 1: Determine the Initial Velocity (u)
The horizontal component of the initial velocity \(u\) can be expressed as:
\[ u_x = u \cos(60^\circ) \]
Given that \(u_x = 19.6 \, \text{m/s}\) and \(\cos(60^\circ) = \frac{1}{2}\), we can set up the equation:
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