An object is projected with a velocity of `30 ms^(-1)` at an angle of `60^(@)` with the horizontal. Determine the horizontal range covered by the object.

Explanation

To determine the horizontal range covered by an object projected at a velocity of \(30 \, \text{m/s}\) at an angle of \(60^\circ\) with the horizontal, we can follow these steps:

### Step 1: Identify the given values
- Initial velocity, \(u = 30 \, \text{m/s}\)
- Angle of projection, \(\theta = 60^\circ\)
- Acceleration due to gravity, \(g = 9.8 \, \text{m/s}^2\)

### Step 2: Use the formula for horizontal range
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