A boy standing on the top of a tower 36 m high has a throw a packet to his friend standing on the ground 48 m horizontally away. If he throws a packet directly aiming the friend with a speed of `10 ms^(-1)`, how short will be packet fall ?

Explanation

To solve the problem step-by-step, we will analyze the motion of the packet thrown by the boy from the top of the tower.

### Step 1: Understand the Problem
A boy is standing on top of a tower that is 36 meters high. He throws a packet horizontally towards his friend who is 48 meters away. The packet is thrown with a speed of 10 m/s. We need to find out how short the packet will fall from the friend's position.

### Step 2: Determine the Angle of Projection
The height of the tower (h) is 36 m, and the horizontal distance (d) to the friend is 48 m. We can find the angle of projection (θ) using the tangent function:
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