Home
Class 11
PHYSICS
A particle moves in xy-plane from positi...

A particle moves in xy-plane from position (2m, 4m) to (6m,8m) is 2s. Magnitude and direction of average velocity is

A

`sqrt(2) ms^(-1)` and `45^(@)`

B

`2sqrt(2) ms^(-1)` and `45^(@)`

C

`4sqrt(2) ms^(-1)` and `30^(@)`

D

`3sqrt(2) ms^(-1)` and `60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B

Displacement, `Deltar = r_(2) - 4 hati +4hatj`
`:. v_(av) = (Delta r)/(Delta t) = (4hati + 4hatj)/(2) = 2(hati +hatj) ms^(-1)`
`rArr` Magnitude of velocity,
`|v_(av)| = 2sqrt(1^(2)+1^(2)) = 2sqrt(2)ms^(-1)`
Direction, `theta = tan^(-1) ((Delta v_(y))/(Deltav_(x))) = tan^(-1) ((2)/(3)) = tan^(-1) 1 = 45^(@)`
Promotional Banner

Topper's Solved these Questions

  • MOTION

    DC PANDEY ENGLISH|Exercise Check Point 4.2|20 Videos
  • MOTION

    DC PANDEY ENGLISH|Exercise Check Point 4.3|10 Videos
  • MOTION

    DC PANDEY ENGLISH|Exercise Medical entrances gallery|19 Videos
  • MEASUREMENT AND ERRORS

    DC PANDEY ENGLISH|Exercise Subjective|19 Videos
  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise (C )Medical entrances gallery|32 Videos

Similar Questions

Explore conceptually related problems

A particle moves in xy-plane from position (1m,2m) to (3m,4m) in 2s. Find the magnitude and direction of average velocity.

An object moves from position (3,4) to (6,5) in the xy-plane. Find the magnitude and direction of displacement vector of the particle.

Velocity of a particle changes from (3hati +4hatj)m//s to (6hati +5hatj)m//s 2s. Find magnitude and direction of average acceleration.

A particle moves in a circle of radius R = 21/22 m with constant speed 1 m//s. Find, (a) magnitude of average velocity and (b) magnitude of average acceleration in 2 s.

In 1.0 s, a particle goes from point A to point B, moving in a semicircle of radius 1.0 m. The magnitude of the average velocity is :-

A particle moves in the x-y plane with a constant acceleration of 1.5m//s^(2) in the direction making an angle of 37^(@) with the x-axis. At t=0 the particle is at the origin and its velocity is 8.0m/s along the x- aixs . Find the velocity and the position of the particle at t = 4.0s.

Two particles of equal mass have coordinates (2m,4m,6m) and (6m,2m,8m). Of these one particle has a velocity v_(1) = (2i)ms^(-1) and another particle has a velocity v_(2) = (2j)ms^(-1) at time t=0. The coordinate of their center of mass at time t=1s will be

A particle movesin the X-Y plane with a constasnt acceleration of 1.5 m/s^2 in the direction making an angle of 37^0 with the X-axis.At t=0 the particle is at the orign and its velocity is 8.0 m/s along the X-axis. Find the velocity and the position of the particle at t=4.0 s.

A charged particle carrying charge q=1muc moves in uniform magnetic with velocity v_1=10^6m//s at angle 45^@ with x -axis in the xy -plane and experiences a force F_1=5sqrt2N along the negative z -axis. When te same particle moves with velocity v_2=10^6m//s along the z -axis it experiences a force F_2 in y -direction. Find a. the magnitude and direction of the magnetic field b. the magnitude of the force F_2 .

A spy plane is being tacked by a radar. At t =0, its position is reported as (100 m ,200 m , 1000 m ). 130 s later, its position is reported to be (2500 m ,1200 m ,1000 m ). Find a unit vector in the direction of plane velocity and the magnitude of its average velocity.