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When a stone is projected which remains ...

When a stone is projected which remains constant?

A

Angular momentum

B

Linear momentum

C

Vertical component of velocity

D

Horizontal component of velocity

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The correct Answer is:
To determine which quantity remains constant when a stone is projected, we can analyze the motion of the stone in terms of its components. Here's a step-by-step solution: ### Step 1: Understand the Components of Motion When a stone is projected, it follows a projectile motion path. This motion can be broken down into horizontal and vertical components. The initial velocity \( u \) can be resolved into: - Horizontal component: \( V_x = u \cos(\theta) \) - Vertical component: \( V_y = u \sin(\theta) \) ### Step 2: Analyze the Forces Acting on the Stone In projectile motion, the only force acting on the stone after it is projected is the gravitational force, which acts downward with a magnitude of \( mg \). This force affects the vertical motion but not the horizontal motion. ### Step 3: Determine the Effect of Gravity on the Components - **Vertical Component (V_y)**: The vertical component of velocity \( V_y \) changes due to the gravitational force. It decreases as the stone rises and increases as the stone falls. Therefore, \( V_y \) is not constant. - **Horizontal Component (V_x)**: The horizontal component of velocity \( V_x \) remains constant because there are no horizontal forces acting on the stone (assuming air resistance is negligible). Thus, \( V_x \) is constant. ### Step 4: Analyze Momentum - **Linear Momentum (p)**: The linear momentum \( p \) of the stone is given by \( p = mV \), where \( V \) is the resultant velocity. Since \( V_y \) is changing, the total linear momentum \( p \) is also changing. - **Angular Momentum (L)**: Angular momentum depends on the linear momentum and the position vector. Since linear momentum is not constant, angular momentum will also not be constant. ### Conclusion From the analysis, we can conclude that the only quantity that remains constant when a stone is projected is the horizontal component of velocity \( V_x \). Thus, the correct answer is: **The horizontal component of velocity remains constant.** ---

To determine which quantity remains constant when a stone is projected, we can analyze the motion of the stone in terms of its components. Here's a step-by-step solution: ### Step 1: Understand the Components of Motion When a stone is projected, it follows a projectile motion path. This motion can be broken down into horizontal and vertical components. The initial velocity \( u \) can be resolved into: - Horizontal component: \( V_x = u \cos(\theta) \) - Vertical component: \( V_y = u \sin(\theta) \) ### Step 2: Analyze the Forces Acting on the Stone ...
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DC PANDEY ENGLISH-MOTION-Check Point 4.2
  1. At the top of the trajectory of a projectile, the directions of its ve...

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  2. At the top of the trajectory of a projectile, the directions of its ve...

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  3. In the motion of a projectile freely under gravity, its

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  4. When a stone is projected which remains constant?

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  5. A stone is projected with speed of 50 ms^(-1) at an angle of 60^(@) wi...

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  6. A football player throws a ball with a velocity of 50 m//s at an angle...

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  7. A particle is projected with a velocity of 20 ms^(-1) at an angle of 6...

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  8. If 2 balls are projected at angles 45^(@) and 60^(@) and the maximum h...

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  9. If the initial velocity of a projectile be doubled, keeping the angle ...

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  10. For a projectile, the ratio of maximum height reached to the square of...

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  11. A particle is projected from ground with speed u and at an angle theta...

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  12. A projectile, thrown with velocity v(0) at an angle alpha to the horiz...

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  13. A particle is projected at an angle of 45^(@) with a velocity of 9.8 m...

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  14. Two projectiles are fired from the same point with the same speed at a...

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  15. A projectile fired with initial velocity u at some angle theta has a ...

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  16. An object is thrown along a direction inclined at an angle of 45^(@) w...

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  17. An object is projected at an angle of 45^(@) with the horizontal. The ...

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  18. The horizontal range of a projectile is 4 sqrt(3) times its maximum he...

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  19. A ball is projected with a velocity 20 sqrt(3) ms^(-1) at angle 60^(@)...

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  20. A projectile is thrown with a velocity of 10 ms^(-1) at an angle of 60...

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