The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is :

Options

A. `theta = tan^(-1) ((1)/(4))`
B. `theta = tan^(-1)(4)`
C. `theta = tan^(-1)(2)`
D. `theta = 45^(@)`

Answer

B

Explanation

Given, `R = H`
Range, `R = (u^(2)(2 sin theta cos theta))/(g)`
Height, `H = (u^(2)sin^(2)theta)/(2g)`
Hence, `(u^(2)(2sin theta cos theta))/(g) = (u^(2)sin^(2)a)/(2g)`
`2 cos theta = (sin theta)/(2) rArr tan theta = 4 rArr theta = tan^(-1)(4)`