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A point starts from rest and moves along...

A point starts from rest and moves along a circular path with a constant tangential acceleration. After one rotation, the ratio of its radial acceleration to its tangential acceleration will be equal to

A

1

B

`2pi`

C

`(1)/(2)pi`

D

`4pi`

Text Solution

Verified by Experts

The correct Answer is:
D
`(a_(n))/(a_(t))=(v^(2)//R)/(a)" "("let a"_(t)=a)`
Here, `v^(2)=2al=2a(2piR)=4piR`. Therefore, the ratio is `(4pi)/(1)`.
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