Home
Class 11
PHYSICS
Assertion In circular motion, dot produc...

Assertion In circular motion, dot product of v and `omega` is always zero.
Reason `omega` is always perpendicular to the plane of the circular motion.

A

If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.

B

If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.

C

If Assertion is true but Reason is false.

D

If Assertion is false but Reason is true.

Text Solution

Verified by Experts

The correct Answer is:
A
v is always perpendicular to `omega`.
Promotional Banner

Similar Questions

Explore conceptually related problems

In circular motion of a particle,

In uniform circular motion

Verticle Circular Motion

During uniform circular motion of a particle

Uniform circular motion is an example of

In a projectile motion the velocity a) is always perpendicular to the acceleration b) is not always perpendicular to the acceleration c) is perpendicular to the acceleration for one instant only d) is perpendicular to the acceleration for two instants.

Consider the two statements related to circular motion in usual notations A. In uniform circular motion vec(omega), vec(v) and vec(a ) are always mutually perpendicular B. In non-uniform circular motion vec(omega) ,vec(v) and vec(a) are always mutually perpendicular

the circular motion of a particle with constant speed is

Assertion: In circular motion, dot product of velocity vector (v) and acceleration vector (a) may be positive, negative or zero. Reason: Dot product of angular velocity vector and linear velocity vector is always zero.

Assertion A charged particle is rotating in a circular path in uniform magnetic field. Then, plane of circle is perpendicular to the magnetic field. Reason Circular motion is a two-dimensional motion.